The density of a solid object that has a mass of 1.62 lb and a volume of 190 mL is 3.87g/mL.
<h3>How to calculate density?</h3>
Density is the measure of the mass of matter contained by a unit volume. It can be calculated by dividing the mass of the substance by its volume.
According to this question, a solid object is said to have a mass of 1.62 lb and a volume of 190 mL.
1 pound = 453.592 grams
1.62 Ibs is equivalent to 734.82 grams
Density of the solid object = 734.82 grams ÷ 190 mL
Density = 3.87g/mL
Therefore, the density of a solid object that has a mass of 1.62 lb and a volume of 190 mL is 3.87g/mL.
Learn more density at: brainly.com/question/20337365
#SPJ1
1. Molarity : 0.25 M
2. mol CH₄ = 7.4 moles
mol O₂ = 14.8 moles
<h3>Further explanation</h3>
1.
Given
83.2 g CuCl2 in 2.5 liters of water
Required
the molarity
Solution
Molarity : mol solute per liter of solution(not per liter of solvent)
mol solute = mol CuCl₂
mol CuCl₂ = mass : MW CuCl₂
mol CuCl₂ = 83.2 : 134.45
mol CuCl₂ = 0.619
Molarity(M) = mol : V
Assume density CuCl₂ = 3.39 g/cm³
volume CuCl₂ = 8.32 g : 3.39 g/cm³ = 2.45 cm³=2.45 x 10⁻³ L
With this small volume value of CuCl₂, the volume of the solute is sometimes neglected in calculating molarity
volume of solution = 2.5 L + 2.45 x 10⁻³ L = 2.50245 L
Molarity(M) = mol : V
M = 0.619 : 2.50245 L = 0.247≈0.25
2.
Given
Reaction
The correct balanced reaction:
CH4 + 2O2 → CO2 + 2H2O
7.4 moles CO2
Required
moles of methane (CH4) and oxygen gas (O2)
Solution
From the equation, mol ratio of CO₂ : CH₄ : O₂ = 1 : 1 : 2
mol CH₄ = mol CO₂ = 7.4 moles
mol O₂ = 2 x mol CO₂ = 2 x 7.4 moles = 14.8 moles
We know, Kinetic energy (movement of the particle) is directly proportional to the temperature of the object. When you decrease the temperature, it's movement will also decrease and object particles move slower.
In short, Your Answer would be Option B
Hope this helps!
Answer:
D They have the same properties.
Explanation:
The same no. of isotopes doesnot describes because isotopes have same symbol but didderent atomic mass.
