The measure of the angle ∠PQR is 90 degrees
<h3>How to prove that ∠PQR is 90 degrees?</h3>
The equation of the line PQ is given as:
3x - y - 2 = 0
The coordinates of the QR are given as:
(0, -2) and (6, -4)
Make y the subject in 3x - y - 2 = 0
y = 3x - 2
The slope of the above line is
m1 = 3
Next, we calculate the slope (m2) of points Q and R.
So, we have:
m2 = (y2- y1)/(x2 - x1)
This gives
m2 = (-4 + 2)/(6 - 0)
Evaluate
m2 = -1/3
The slopes of perpendicular lines are opposite reciprocals.
m1 = 3 and m2 = -1/3 are opposite reciprocals.
This means the lines PQ and QR are perpendicular lines.
The angle at the point of perpendicularity is 90 degrees
Hence, the measure of the angle ∠PQR is 90 degrees
Read more about linear equations at:
brainly.com/question/15602982
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So you first need to calculate 8y 2 which is basically 8x2 which equals 16 then add 16y + 17y which is 33 so your answer is 33y+2
The radius of circle C is also 3 times greater than the radius of circle D.
The area of circle C:
A C = (3r)² π = 9 r² π
The area of circle D:
A D = r² π
9 r² π : r ² π = 9
Answer: It is 9 times the area of circle D.
It is 10 times bigger. It is easy because you can do 50 x 10 which is 500 and you know it is 10 times bigger.
I can’t see it it’s to blurry for me
