I need help on everything

Snezhnost [94]

Answer:B 55

Step-by-step explanation:

3 0

2 years ago

Jonathan collects postcards and stamps. The number of postcards in his collection is 12 more than 3/4 the number of stamps. He h

d1i1m1o1n [39]

Answer:

$12 + \frac{3}{4} x = 39$

$\frac{3}{4} x = 27$

$x = 36$

Jonathan has 36 stamps.

7 0

1 year ago

PLEASE HELP WITH THIS QUESTION! WILL MARK BRAINLIEST

sweet [91]

We know that
[scale factor ]=[real]/[drawing]
[real]=[drawing]*[scale factor ]

step 1
find the real values

if the base of Riley's drawing is 10 centimeters
[real]=[drawing]*[scale factor ]--------> 10*3-------> 30 cm
the base of the triangular clock face is 30 cm

the height of Riley's drawing is 15 centimeters
[real]=[drawing]*[scale factor ]--------> 15*3-------> 45 cm
the height of the triangular clock face is 30 cm

the area of the triangular clock face is-----> 45*30/2-------> 675 cm²

the answer is the option C. 675 square centimeters

4 0

3 years ago

Read 2 more answers

Evaluate the following limit:

Makovka662 [10]

If we evaluate the function at infinity, we can immediately see that:

$\large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle L = \lim_{x \to \infty}{\frac{(x^2 + 1)^2 - 3x^2 + 3}{x^3 - 5}} = \frac{\infty}{\infty}} \end{gathered}$}$

Therefore, we must perform an algebraic manipulation in order to get rid of the indeterminacy.

We can solve this limit in two ways.

By comparison of infinities:

We first expand the binomial squared, so we get

$\large\displaystyle\text{$\begin{gathered}\sf \displaystyle L = \lim_{x \to \infty}{\frac{x^4 - x^2 + 4}{x^3 - 5}} = \infty \end{gathered}$}$

Note that in the numerator we get x⁴ while in the denominator we get x³ as the highest degree terms. Therefore, the degree of the numerator is greater and the limit will be \infty. Recall that when the degree of the numerator is greater, then the limit is \infty if the terms of greater degree have the same sign.

Dividing numerator and denominator by the term of highest degree:

$\large\displaystyle\text{$\begin{gathered}\sf L = \lim_{x \to \infty}\frac{x^{4}-x^{2} +4 }{x^{3}-5 } \end{gathered}$}\\$

$\ \ = \lim_{x \to \infty\frac{\frac{x^{4} }{x^{4} }-\frac{x^{2} }{x^{4}}+\frac{4}{x^{4} } }{\frac{x^{3} }{x^{4}}-\frac{5}{x^{4}} } }$

$\large\displaystyle\text{$\begin{gathered}\sf \bf{=\lim_{x \to \infty}\frac{1-\frac{1}{x^{2} } +\frac{4}{x^{4} } }{\frac{1}{x}-\frac{5}{x^{4} } } \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =\frac{1}{0}=\infty } \end{gathered}$}$

Note that, in general, 1/0 is an indeterminate form. However, we are computing a limit when x →∞, and both the numerator and denominator are positive as x grows, so we can conclude that the limit will be ∞.

5 0

2 years ago

1. Are the polygons similar?

jeyben [28]

The polygons are similar.

This is because dividing the corresponding sides forms the same ratio, as shown by the three equations below

35/28 = 1.25

25/20 = 1.25

(15.5)/(12.4) = 1.25

So the larger figure on the right has side lengths that are 1.25 times larger compared to the corresponding sides of the figure on the left.

You'll need to flip the figure on the left so that the side labeled "20" is along the top, and the "28" is along the bottom.

After this flip happens, also note that the angle arc markings match up. The bottom pairs of angles of each figure are shown with a single arc, while the top angles are shown as double arcs. This helps visually show which angles pair up and are congruent to one another.

Because we have similar proportions as discussed earlier, and congruent pairs of angles like this, this shows the two figures are similar quadrilaterals. The one on the right is simply an enlarged scaled up copy of the figure on the left.

3 0

2 years ago