Answer:
The maximum height of the ball is 256m
Step-by-step explanation:
Given the equation of a pathway modelled as pathway can be modeled by h = -16t² + 128t
At maximum height, the velocity of the ball is zero.
velocity = dh/dt
velocity = -32t + 128
Since v = 0 at maximum height
0 = -32t+128
32t = 128
t = 128/32
t = 4seconds
The maximum height can be gotten by substituting t = 4 into the modelled equation.
h = -16t² + 128t
h = -16(4)²+128(4)
h = -16(16)+512
h = -256+512
h = 256m
Answer:
need points for school i have to have 50 points by 3 pm ill owe u promise :)
Step-by-step explanation:
The digital time for quarter past three is 3:15, it is 15 minutes past 3 o'clock.
Ok so 8:12 can be 8 to 12, or 8\12
do that help?
Answer:
12, 17
Step-by-step explanation:
Two sides must add up to a greater sum than that of the remaining side
