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lukranit [14]
3 years ago
12

Find the quotient. 95 92

Mathematics
1 answer:
Nostrana [21]3 years ago
3 0

Answer:

1.033

Step-by-step explanation:

95

92     does not actually represent a quotient.  Write the quotient as

 95

------- = 1.033

 92

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Help me on this question.
NISA [10]
This question involves direct proportion which has the formula (y=kx) where y and x are the values which are proportional and k is the constant of proportionality.

The constant of proportionality is basically the value that stays the same even if the x and y values change.

In this case, the constant of proportionality would be 3/7.
6 0
2 years ago
1. What number is 35% of 80?<br>​
Stella [2.4K]

Answer: 28

Step-by-step explanation: 80 x 0.35 = 28

6 0
2 years ago
Read 2 more answers
The amount of money Tom has is 75% of Sallys amount of money. After Sally spent $120 and Tom saved all his money Tom's amount of
egoroff_w [7]

Answer: sally initially has $240, Tom initially has $180.

Step-by-step explanation:

Let initial amount of money sally has = x

Then, initial amount tom has = 75% * x = 0.75x

Now to present,

Amount sally has = x -120

Amount tom has = [x - 120] + [50% * (x-120)]

= x - 120 + 0.5x - 180

= 1.5x - 180

Since Tom didn't spend, it means this is the same amount tom has then we equate both equations.

0.75x = 1.5x - 180

180 = 0.75x

x = 240

Therefore, initial money of sally of sally = $240

Initial money of tom = 240 * 0.75 = $180.

6 0
3 years ago
A consumer group has determined that the distribution of life spans for gas ranges (stoves) has a mean of 15.0 years and a stand
Art [367]

Answer:

b. Mean = 1.6 years, standard deviation - 0.92 years, shape: approximately Normal.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction of normal Variables:

When we subtract normal variables, the mean is the subtraction of the means, while the standard deviation is the square root of the sum of the variances.

A consumer group has determined that the distribution of life spans for gas ranges (stoves) has a mean of 15.0 years and a standard deviation of 4.2 years. Sample of 35:

This means that:

\mu_G = 15

s_G = \frac{4.2}{\sqrt{35}} = 0.71

The distribution of life spans for electric ranges has a mean of 13.4 years and a standard deviation of 3.7 years. Sample of 40:

This means that:

\mu_E = 13.4

s_E = \frac{3.7}{\sqrt{40}} = 0.585

Which of the following best describes the sampling distribution of the difference in mean life span of gas ranges and electric ranges?

Shape is approximately normal.

Mean:

\mu = \mu_G - \mu_E = 15 - 13.4 = 1.6

Standard deviation:

s = \sqrt{s_G^2+s_E^2} = \sqrt{0.71^2+0.585^2} = 0.92

So the correct answer is given by option b.

8 0
3 years ago
Determine the value of x to the nearest thousandth in the equation 8(2)^x+3=48
solong [7]

You probably mean either

8\cdot2^x + 3 = 48

or

8\cdot2^{x+3} = 48

Write 8 = 2³, so that in the first interpretation,

8\cdot2^x = 2^3 \cdot 2^x = 2^{x + 3}

and in the second,

8\cdot2^{x+3} = 2^3 \cdot 2^{x+3} = 2^{x + 6}

Then in the first interpretation, we have

2^{x + 3} + 3 = 48 \implies 2^{x + 3} = 45 \implies x + 3 = \log_2(45) \implies x = \log_2(45) - 3 \approx \boxed{2.492}

Otherwise, the second interpretation gives

2^{x + 6} = 48 \implies x + 6 = \log_2(48) \implies x = \log_2(48) - 6 \approx -0.415

8 0
2 years ago
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