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Kamila [148]
3 years ago
15

Go to the sd_messier.html file. Within the document head, create links to the sd_base.css, sd_layout.css, and sd_effects.css sty

le sheet files in the order listed. Study the content and structure of the web page before moving onto the next step.
Engineering
1 answer:
makkiz [27]3 years ago
6 0

Answer:

Explanation:

1. Inside tss_coach.html <head> section, include these two lines of code:

<link rel="stylesheet" href="coach_layout.css">

<link rel="stylesheet" href="coach_styles.css">

These two lines links the CSS files with the HTML code.

2. Include the below two lines at the top of the file coach_styles.css and before the comment section

@charset "UTF-8"

@font-face { font-family: Nobile;

src: url (nobile-webfont.woff); }

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Use pseudocode. 1) Prompt for and input a saleswoman's sales for the month (in dollars) and her commission rate (percentage). Ou
aleksandr82 [10.1K]

Answer:

The pseudocode is as follows:

Input SalesAmount

Input CommissionRate

CommissionEarned= SalesAmount * (CommissionRate/100)

Print CommissionEarned

Explanation:

This gets input for SalesAmount

Input SalesAmount

This gets input for CommissionRate

Input CommissionRate

This calculates the CommissionEarned

CommissionEarned= SalesAmount * (CommissionRate/100)

This prints the calculated CommissionEarned

Print CommissionEarned

3 0
3 years ago
What Do Solar Engineers Do?
konstantin123 [22]
Plan, design, and implement solar energy projects
7 0
3 years ago
A liquid water turbine receives 2 kg / s water at 2000 kPa, 20°C with a velocity of 15 m / s . The exit is at 100 kPa, 20°C, a
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3 years ago
What will happen in a wire drawing operation when the cross-sectional area has a reduction of 60% in a single pass?
Fofino [41]

Answer:

DRAWING LOAD IS  3.67 A_{O}\sigma

Explanation:

wire drawing is a method of obtaining wire of bigger large diameter from iron rod . it is cold process which need die to obtain wire

drawing load for wire drawing is given as P = A_{F}*\sigma*ln(\frac{A_{O}}{A_{F}})

Where A f is initial area, Ao is original area, σ is yield stress

as given in question sectional area reduce 60%, therefore

A_{f} = A_{O}- 0.6A_{O}

    = 0.4 A_{O}

Due to change in area ,drawing load p is

p = 0.4A_{O}*\sigma*ln(\frac{A_{O}}{0.4A_{O}})

p = 3.67 A_{O}\sigma

4 0
3 years ago
A single phase, 50-KVA, 2400-240-volt, 60 Hz distribution transformer has the following parameters: •
never [62]

Answer:

B) voltage at the sending end of the feeder = 2483.66 v

Explanation:

attached below is the the equivalent circuits and the remaining solution  for option A

B) voltage = 2400 v

   I  = \frac{50*10^3}{2400}  =  20.83 A

calculate voltage at sending end ( Vs )

Vs = 2400 +  20.83 ∠ -cos^-1 (0.8) ( 0.75*2 + 0.5 + j 2 + j2 )

hence Vs = 2483.66 ∠ 0.961

therefore voltage at the sending end = 2483.66 v

8 0
4 years ago
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