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Scilla [17]
3 years ago
6

A household refrigerator runs one-fourth of the time and removes heat from the food compartment at an average rate of 800 kJ/h.

If the COP of the refrigerator is 2.4, determine the power the refrigerator draws when running.
Engineering
1 answer:
Aleksandr [31]3 years ago
6 0

Answer:

The power the refrigerator draws when running = 0.37 Kw

Explanation:

Since the household refrigerator runs one-fourth of the time ;

The refrigerator will remove heat at the rate of;

QL = 4 x (800 Kj/h) = 3200 Kj/h

The formula to determine the power the refrigerator draws when running is;

W(in) = QL/COP

Thus;

W(in) = 3200/2.4 = 1333.33 Kj/h

This is in Kj/h and the unit of Power is in kw. We know that 1kw = 3600 kj/h

Thus;

1333.33Kj/h = (1333.33Kj/h x 1kw)/3600 kj/h = 0.37 kw

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