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nignag [31]
3 years ago
12

Find the coordinates of the other endpoint of AB with A(6,-4) and (3,10) as the midpoint

Mathematics
1 answer:
Oxana [17]3 years ago
3 0
Answer is B(0,24) . I try my best to help you . Hope can help you.

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Felicia wants to buy a new soccer ball. it is on sale for $12.60 She has one $10 bill,two $5 bills,three$1 bills,6 quarters,and
gladu [14]
One $10 bill, Two $1 bills, Two Quarters, Two Nickels

Two $5 bills, Two $1 bills, Two Quarters, Two Nickles

One $10 bill, One $1 bill, Six Quarters, Two Nickles


5 0
3 years ago
Which equation has the solutions x = -3 ± √3i/2 ?
Maurinko [17]

Answer:Answer is option C : [x^{2} + 3x + 3 ] =0

Note:  None of options matches with given question.

instead of "-3" , there should be "-\frac{3}{2}".

Step-by-step explanation:

Note:  None of options matches with given question.

instead of "-3" , there should be "\frac{3}{2}".  

Here, First thing you have to observe the nature of roots.

∴ x = -\frac{3}{2}+\frac{\sqrt{3}}{2}i and x = -\frac{3}{2}-\frac{\sqrt{3}}{2}

∴ [ x+(\frac{3}{2}-\frac{\sqrt{3}}{2}i) ][ x+(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ]=0

∴ [ x^{2} + x(\frac{3}{2}+\frac{\sqrt{3}}{2}i)+ x(\frac{3}{2}-\frac{\sqrt{3}}{2}i) + (\frac{3}{2}-\frac{\sqrt{3}}{2}i)(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ]=0

∴ [x^{2} + \frac{3}{2}x + \frac{\sqrt{3}}{2}ix + \frac{3}{2}x - \frac{\sqrt{3}}{2}ix + (3-\frac{\sqrt{3}}{2}i)(3+\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + (\frac{3}{2}-\frac{\sqrt{3}}{2}i)(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + \frac{9}{4} - (\frac{\sqrt{3}}{2}i)(\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + \frac{9}{4} - (\frac{3}{4}) i^{2} ] =0

∴ [x^{2} + 3x + \frac{9}{4} + (\frac{3}{4}) ] =0

∴ [x^{2} + 3x + \frac{12}{4} ] =0  

∴ [x^{2} + 3x + 3 ] =0  

Thus, Answer is option C : <em>[x^{2} + 3x + 3 ] =0  </em>

6 0
3 years ago
Which statement is true about this equation?
Vlad [161]

Answer:

D

Step-by-step explanation:

-9x-27+12 = -6x-15-3x

0=0

D) the equation has infinitely many solutions

4 0
2 years ago
Which equation is the equation of the line, in point-slope form, that has a slope of 2 and passes through the point (-8, 1)?
lutik1710 [3]

Answer:

y=2x+17

Step-by-step explanation:

y-y1=m(x-x1)

y-1=2(x-(-8))

y-1=2(x+8)

y=2x+16+1

y=2x+17

5 0
2 years ago
If X squared equals 16 then X equals 4
AfilCa [17]
That would be correct because if x times x =16 than that means that the square root of 16 is 4
6 0
3 years ago
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