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serg [7]
3 years ago
6

Which of the following graphs represents a function? Graph A (parabola) Graph B (hyperbola) Graph C (circle) Graph D (horizontal

parabola)
Mathematics
1 answer:
ale4655 [162]3 years ago
3 0
Graph A is a function. A function is defined as a graph that has one x for every y value. To verify this, you can use the vertical line test. When a vertical line is held to any portion of the graph, it should intersect the graph only once. This is only true for a parabola, proving it is the function.
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(5x^2+38x+18) divided (x+7) what is the quotient and the remainder
xxTIMURxx [149]
The quotient is 5x^2 + 3x -3 and the remainder is -3.
5 0
2 years ago
Daniel had $57 to spend on gifts he spent $10.51 on a gift for Isaac $8.73 on a gift for madison and $8.47 on a gift for Abigail
mina [271]
57-10.51=46.49
46.49-8.73=37.76
37.76-8.47=29.29
Therefore Daniel has $29.29 left.
7 0
2 years ago
Read 2 more answers
Represent the following expressions as a power of the number a (a≠0): c ((a2)−2)5÷(a4a)3
s2008m [1.1K]

Answer:

1/a²⁷

Step-by-step explanation:

Given: $ \frac{((a^2)^{-2})^5}{a^4.a^3} $

We know that when the bases are same the powers can be added. i.,e.,

                                           (xᵃ)ᵇ = x ⁽ᵃ ⁺ ᵇ⁾

⇒ $ \frac{((a^2)^{-2})^5}{a^4.a^3} \implies \frac{(a^2)^{-10}}{a^7} $

$  \implies \frac{a^{-20}}{a^7} = a^{-20 - 7} = a^{-27} $

Also, $ \frac{x^a}{x^b} = x^{a - b} $

This is nothing but, $ \frac{1}{a^{27}} $.

Note that $ a $ cannot be zero here. The condition is provided in the question as well.

7 0
2 years ago
4 2/7 ÷3 4/5=<br> how do you answer this?​
Pavel [41]

is it 42 or 4 and 2 separate

6 0
3 years ago
URGENT PLEASE HELP
Inga [223]

Answer:

y = - \frac{1}{3} x + 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 3x - 3 ← is in slope- intercept form

with slope m = 3

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{3}, hence

y = - \frac{1}{3} x + c ← is the partial equation of the perpendicular line

To find c substitute (3, 1) into the partial equation

1 = - 1 + c ⇒ c = 1 + 1 = 2

y = - \frac{1}{3} x + 2 ← equation of perpendicular line

4 0
2 years ago
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