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3 years ago

I need help on this I am just going to use the picture

Mathematics

2 answers:

iren [92.7K]3 years ago

8 0

D is the correct answer

Radda [10]3 years ago

4 0

Answer:

Step-by-step explanation:

let y = f(x), that is

y = $\frac{2x-3}{5}$

Rearrange making x the subject

Multiply both sides by 5

5y = 2x - 3 ( add 3 to both sides )

5y + 3 = 2x (divide both sides by 2 ) , then

x = $\frac{5y+3}{2}$

Change y back into term of x, hence

$f^{-1}$ (x) = $\frac{5x+3}{2}$ → D

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Decide whether quadrilateral JKLM is a rectangle, a rhombus, or a square. More than one answer may apply!

NARA [144]

Answer:

Square.

Step-by-step explanation:

given J(-4,2) || K(0,3) || L(1,-1) || M(-3,-2)

given below the visual answer.

you can find the distance of coordinate to coordinate:

Distance of JK

√(-4-0)² + (2-3)²

√17

Distance of KL

√(0-1)²+(3--1)²

√17

Distance of LM

√(1--3)²+(-1--2)²

√17

Distance of MJ

√(-3--4)²+(-2-2)²

√17

All sides are similar of √17 , so its a square.

4 0

3 years ago

Read 2 more answers

(3-4i)(6i+7)-(2-3i)

Sergeu [11.5K]

Answer:

43-7i

Step-by-step explanation:

We are given the expression:

$\displaystyle \large{(3 - 4i)(6i + 7) - (2 - 3i)}$

First, expand 3-4i in 6i+7. To expand binomial with binomial, first we expand 3 in 6i+7 then expand -4i in 6i+7.

$\displaystyle \large{[(3 \cdot 6i) + (3 \cdot 7) + ( - 4i \cdot 6i) + ( - 4i \cdot 7)]- (2 - 3i)} \\ \displaystyle \large{[18i + 21 - 24 {i}^{2} - 28i]- (2 - 3i)}$

Now combine like terms.

$\displaystyle \large{[ - 10i+ 21 - 24 {i}^{2} ]- (2 - 3i)}$

Imaginary Unit

$\displaystyle \large{i = \sqrt{ - 1} } \\ \displaystyle \large{ {i}^{2} = - 1 }$

Therefore:-

$\displaystyle \large{[ - 10i+ 21 - 24 ( - 1) ]- (2 - 3i)} \\ \displaystyle \large{[ - 10i+ 21 + 24]- (2 - 3i)} \\ \displaystyle \large{[ - 10i+ 45]- (2 - 3i)}$