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Ksivusya [100]
3 years ago
5

Ashley and losa each improved their yards by planting dayliles and shrubs. They bought their supplies from the same store. Ashle

y spent $45 on 7 daylilies and 2 shrubs. Lisa spent $174 on 14 daylilies and 11 shurbs. What is the cost of one daylily and the cost of one scrub?
Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
5 0

Let x be cost of one daylily and y be the cost of one scrub.

Ashley spent $45 on 7 daylilies and 2 shrubs. 7 daylilies cost 7x and 2 shrubs cost 2y, in total 7x+2y that is $45. The first equation is 7x+2y=45.

Lisa spent $174 on 14 daylilies and 11 shurbs. 14 daylilies cost 14x and 11 shrubs cost 11y, in total 14x+11y that is $174. The second equation is 14x+11y=144.

Solve this system. Wit hthis aim multiply first equation by 2 and the subtract second equation from first:

2·(7x+2y)-(14x+11y) =2·45-174,

14x+4y-14x-11y=90-174,

-7y=-84,

7y=84,

y=84÷7,

y=12.

Then substitute into first equation:

7x+2·12=45,

7x+24=45,

7x=45-24,

7x=21,

x=21÷7,

x=3.

Answer: the cost of one daylily is $3 and the cost of one scrub is $12.

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fiasKO [112]

Missing Part of the Question

  • 3 (4 - y) -7 ; 5 + 3y
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  • 2y + 7 + y - 2 + y; 4y + 5

Answer:

  • 2y + 7 + y - 2 + y; 4y + 5

Step-by-step explanation:

Given

y = 3

Required

Which pair of expression are equal

To get the pair of expression that are equal; we simply substitute 3 for y in each of the expressions

3 (4 - y) -7 and 5 + 3y

<em>Substitute 3 for y in 3 (4 - y) -7</em>

This gives 3(4 - 3) -7

= 3(1) - 7

= 3 - 7

= -4

<em>Then Substitute 3 for y in 5 + 3y</em>

This gives  5 + 3(3)

= 5 + 9

= 14

-4 and 14 are not equal

---------------------------------------------------------------------------------------

9 + y + 4y - 2 - 3y; -2y + 7

<em>Substitute 3 for y in </em>9 + y + 4y - 2 - 3y

This gives 9 + 3 + 4(3) - 2 - 3(3)

= 9 + 3 + 12 - 2 - 9

= 13

<em>Then Substitute 3 for y in -2y + 7</em>

This gives  -2(3) + 7

= -6 + 7

= 1

13 and 1 are not equal

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5 + y - 2 - 6y + y; 8y + 3

<em>Substitute 3 for y in 5 + y - 2 - 6y + y</em>

This gives 5 + 3 - 2 - 6(3) + 3

= 5 + 3 - 2 - 18 + 3

= -9

<em>Then Substitute 3 for y in 8y + 3</em>

This gives  8(3) + 3

= 24 + 3

= 27

-9 and 27 are not equal

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2y + 7 + y - 2 + y; 4y + 5

<em>Substitute 3 for y in 2y + 7 + y - 2 + y</em>

This gives 2(3) + 7 + 3 - 2 + 3

= 6 + 7 + 3 - 2 + 3

= 17

<em>Then Substitute 3 for y in 4y + 5</em>

This gives  4(3) + 5

= 12 + 5

= 17

17 and 17 are equal

Hence, Option D is correct

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3 years ago
Factorise the following.​
zepelin [54]

Answer:

Step-by-step explanation:

i). \frac{48a^3}{6a}=\frac{6\times 8\times a\times a^2}{6a}

          =\frac{6a}{6a}\times 8a^2

          = 8a²

ii). \frac{72a^3b^4c^5}{8ab^2c^3} = \frac{8\times 9\times a\times a^2\times b^2\times b^2\times c^2\times c^3}{8ab^2c^3}

                = \frac{8ab^2c^3}{8ab^2c^3}\times 9a^2b^2c^2

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Ilia_Sergeevich [38]

Answers are in bold:

-1=3x-2

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-1+2=3x-2+2

1=3x

divide both sides by 3

1÷3=3x÷3

1/3=x

-3x=9

divide both sides by -3

-3x÷-3=9÷-3

x=-3

-10=-5x

divide both sides by -5

-10÷-5=-5x÷-5

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I hope this is good enough:

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x = 495/5
x = 99

x + 1 = 99 + 1 = 100
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Answer:

He is left with 5 feet and 10 inches.

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