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GarryVolchara [31]
3 years ago
12

Anyone help please I’m wasting my points for no reason

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
8 0

Answer:

Qn1: -37

Qn2: 16

Qn3:-33.6

Step-by-step explanation:

<u>Qn1:</u>

k(4) = -4*4-6 = -16-6 = -22

m(5) = (5^2)-8*5=-15

k(4)+m(5)= -22+ (-15)= -37

<u>Qn2:</u>

m(-2)= 4 -8*(-2)= 20

n(10) = 2 -6 = -4

20+ (-4)=16

<u>Qn3:</u>

n(-100)= -20-6 = -26

k(-8) = -1.6 -6= -7.6

-26+ (-7.6) = -33.6

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vovangra [49]
B. is the answer I believe since most are not functions
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3 years ago
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Which of the following best describes the equation below? y=-6x+7
Hitman42 [59]

Answer:

y=-6x+7    (Negative Slope)

Step-by-step explanation:

This equation is in slope intercept form.

7= y-intercept

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5 0
3 years ago
<img src="https://tex.z-dn.net/?f=-2%5Csqrt%7B18%7D%20%2B2%5Csqrt%7B2%7D" id="TexFormula1" title="-2\sqrt{18} +2\sqrt{2}" alt="-
UkoKoshka [18]

Answer:

- 4\sqrt{2}

Step-by-step explanation:

Using the rule of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab}

Simplify \sqrt{18} using this rule

\sqrt{18}

= \sqrt{9(2)}

= \sqrt{9} × \sqrt{2} = 3\sqrt{2}

Then

- 2\sqrt{18} + 2\sqrt{2}

= - 2(3\sqrt{2} ) + 2\sqrt{2}

= - 6\sqrt{2} + 2\sqrt{2}

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5 0
3 years ago
An athlete jumped 5.5 feet which was 1.1 times higher than the previous jumper how high did the previous athlete jump
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Answer:

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3 0
3 years ago
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What 2 numbers add to get 2 and multiply to 4
rusak2 [61]
Factor 4
4=1 times 4
2 times 2
they don't add to 2
set up equation
x+y=2
xy=4

first equation, subtract x from both sides
y=2-x
subsitute for y
x(2-x)=4
distribute
2x-x^2=4
add x^2
2x=x^2+4
subtract 2x
0=x^2-2x+4
use quadratic formula which is
if you have ax^2+bx+c=0 then
x=\frac{ -b+/-\sqrt{b^{2}-4ac} }{2a} so

1x^2-2x+4=0
a=1
b=-2
c=4
x=\frac{ -(-2)+/-\sqrt{(-2)^{2}-4(1)(4)} }{2(1)}
x=\frac{ 2+/-\sqrt{4-16} }{2}
x=\frac{ 2+/-\sqrt{-12} }{2}
we have \sqrt{-12} and that doesn't give a real solution
therefor there are no real solutions
but if you want to solve fully
x=\frac{ 2+/-2\sqrt{-3} }{2}
i=\sqrt{-1}
x=\frac{ 2+/-2i\sqrt{3} }{2}
x=1+/-i\sqrt{3}
x=1-i\sqrt{3} or x=1+i\sqrt{3} (those are the 2 numbers)

 





6 0
4 years ago
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