Let after n week both tanks have same quantity of water .
for first tank
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tank hold 540 gallon of water ,
leaking of water 4 gallon /week
so, in n week water leak from the tank =4× n = 4n
now, after n week quantity of water in the tank = 540 -4n
for second tank
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quantity of water in the tank =720 gallon
leaking of water at the rate = 7gallon/week
so, after n week water leak from the tank = 7× n =7n
after n week quantity of water rest in the tank = 720 -7n
now ,
according to question ,
water in first tank = water in second tank
540 -4n = 720 -7n
7n -4n = 720 -540
3n = 180
n = 60
hence , after 60 week both tank have same quantity of water.
Answer:
first y then x because y represents 22 and x represents 4 a week.
Answer:
D) y = -1/2x + 4
Step-by-step explanation:
Points on the graph: (0, 4) and (8, 0)
Slope:
m=(y2-y1)/(x2-x1)
m=(0 - 4)/(8-0)
m= -4/8
m = -1/2
Slope-intercept:
y - y1 = m(x - x1)
y - 4 = -1/2(x - 0)
y - 4 = -1/2x
y = -1/2x + 4
