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yawa3891 [41]
4 years ago
15

" alt="f(x)=9 x^{3} +2x^2-5x+4" align="absmiddle" class="latex-formula"> and g(x)=5x^3-7x+4. What is f(x)-g(x)? Show all of your steps and write your finial answer in factored form.
Mathematics
2 answers:
Fudgin [204]4 years ago
6 0
F(x)= 9x^3+ 2x^2 -5x+ 4

g(x)= 5x^3 -7x+ 4

f(x) - g(x)
= (9x^3+ 2x^2 -5x+ 4) - (<span>5x^3 -7x+ 4)
= </span><span>9x^3+ 2x^2 -5x+ 4 -5x^3+ 7x -4
= (9x^3 -5x^3)+ 2x^2+ (7x -5x)+ (4-4) (combine like terms)
= 4x^3+ 2x^2+ 2x
= 2x* (2x^2+ x+ 1)

The final answer is </span><span>2x* (2x^2+ x+ 1).</span>
Simora [160]4 years ago
4 0

Answer:

Step-by-step explanation:

f(x)= 9x^3+ 2x^2 -5x+ 4

g(x)= 5x^3 -7x+ 4

f(x) - g(x)

= (9x^3+ 2x^2 -5x+ 4) - (5x^3 -7x+ 4)

= 9x^3+ 2x^2 -5x+ 4 -5x^3+ 7x -4

= (9x^3 -5x^3)+ 2x^2+ (7x -5x)+ (4-4) (combine like terms)

= 4x^3+ 2x^2+ 2x

= 2x* (2x^2+ x+ 1)

The final answer is 2x* (2x^2+ x+ 1).

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