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denis23 [38]
3 years ago
14

A town has a population of 7000 and grows at 3% every year. To the nearest year, how long will it be until the population will r

each 12400?
Mathematics
1 answer:
Gelneren [198K]3 years ago
7 0

Answer: It takes almost 19 years to reach the population of 12400.

Step-by-step explanation:

Since we have given that

Initial Population = 7000

Rate of growth = 3% every year

Final population = 12400

We need to find the number of years.

As we know the formula for "Compound Interest":

A=P(1+\frac{r}{100})^n\\\\12400=7000(1+\frac{3}{100})^n\\\\\frac{12400}{7000}=\frac{103}{100}^n\\\\\frac{124}{70}={1.03}^n\\\\1.771=1.03^n\\\\\text{ Taking logarithms on both the sides}\\\\\log 1.77=n\log 1.03\\\\n=\frac{\log 1.77}{\log 1.03}\\\\n=19.31\\\\n=19\ yrs

Hence, It takes almost 19 years to reach the population of 12400.

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A peach orchard owner wants to maximize the amount of peaches produced by her orchard.
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  c) dT/dx = {900, x≤30; 2100-80x, x>30}

Step-by-step explanation:

a) The problem statement gives the function for x ≤ 30, and gives an example of evaluating the function for x = 35. So, replacing 35 in the example with x gives the function definition for x > 30.

\displaystyle Y(x)=\left\{\begin{array}{lcl}900&\text{for}&x\le 30\\900-40(x-30)&\text{for}&x>30\end{array}\right.

__

b) The yield per acre is the product of the number of trees and the yield per tree:

  T(x) = x·Y(x)

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__

c) The derivative is ...

\displaystyle\frac{dT}{dx}=\left \{\begin{array}{lcl}900&\text{for}&x\le 30\\2100-80x& \text{for}&x>30\end{array}\right.

_____

The attached graph shows the yield per acre (purple, overlaid by red for x<30), the total yield (black), and the derivative of the total yield (red). You will note the discontinuity in the derivative at x=30, where adding one more tree per acre suddenly makes the rate of change of yield be negative.

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