Answer:
4x-y+1=0
Step-by-step explanation:
here,given equation of a line id
4x-y-2=0.. eqn(i)
equation of any line parallel to line (i) is
4x-y+k=0...eqn(ii)
since, the line(ii) passes through (1,5)[replacing x=1 and y=5 in eqn(ii), we get]
4*1-5+k=0
or, 4-5+k=0
or,-1+k=0
•°•k=1
substituting the value of k=1 in eqn(ii),
4x-y+1=0 is the required equation of the line.
2(x +4)-6(q/9)
The slash represents a division sign.
Answer:
Step-by-step explanation:
Let (x,y) be midpoint of P(3,4) & Q(5,−2)
Midpoint formula for two points (a,b) and (c,d) is
(x,y) =(
2
a+c
,
2
b+d
).
x=
2
3+5
=4
y=
2
4−2
=1
∴ (x,y)=(4,1)
Answer:
Option D.
Step-by-step explanation:
The given quadratic equation is
We need to draw the graph of given equation by using graphing calculator as shown below.
From the graph it is clear that the parabola intersect the x-axis at points (-2,0) and (-5,0). So, the x-intercepts are (-2,0) and (-5,0).
Therefore, the correct option is D.
Answer:
Step-by-step explanation:
y + 3 = 7(x - 1)
y + 3 = 7x - 7
y = 7x - 10
