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xxMikexx [17]
3 years ago
12

Reflect the triangle (-2,-2) (-6,-8) (-8,-8) over the x-axis. What are the new vertices?

Mathematics
1 answer:
Inessa [10]3 years ago
5 0
Reflecting across the x axis changes the y value to the opposite, but doesn't change the x value, so the new values are:
(-2,2), (-6, 8), (-8, 8)
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Ethan started of with 246,000 Twitter followers

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What is the value of x ??
mr Goodwill [35]

Answer:

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Step-by-step explanation:

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Read 2 more answers
Simplify (a^-2*b^2/a^2*b^-1)<br><br><br> The answer is B
Ad libitum [116K]

Answer:

=b/a^4

Step-by-step explanation:

6 0
2 years ago
Which of the following trigonometric inequalities has no solution over the interval 0 ≤ x ≤ 2pi radians?
valentinak56 [21]

Answer:

A .cos(x)<1

Step-by-step explanation:

According to the first inequality

cos(x)<1

x < arccos 1

x<0

This therefore does not have a solution within the range 0 ≤ x ≤ 2pi

x cannot be leas than 0. According to the range not value, 0≤x which is equivalent to x≥0. Thus means otvis either x = 0 or x> 0.

For the second option

.cos(x/2)<1

x/2< arccos1

x/2<0

x<0

This inequality also has solution within the range 0 ≤ x ≤ 2pi since 0 falls within the range of values.

For the inequality csc(x)<1

1/sin(x) < 1

1< sin(x)

sinx>1

x>arcsin1

x>90°

x>π/2

This inequality also has solution within the range 0 ≤ x ≤ 2pi since π/2 falls within the range of values

For the inequality csc(x/2)<1

1/sin(x/2) < 1

1< sin(x/2)

sin(x/2)> 1

x/2 > arcsin1

X/2 > 90°

x>180°

x>π

This value of x also has a solution within the range.

Therefore option A is the only inequality that does not have a solution with the range.

6 0
3 years ago
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