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3 years ago

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Which of these is the algebraic expression for "nine less than some number?" Fraction 9 over k Fraction k over 9 9 − k k − 9. MI

DDLE

1 answer:

alexira [117]3 years ago

7 0

<h3>Answer: k - 9</h3>

We have some number k and we take 9 from it to end up with k-9, which represents 9 less than k.

For example, if k = 12, then k-9 = 12-9 = 3. So 3 is nine less than the number k = 12.

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Four is the quotient of 24 divided by some number. What is the number?

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What is the value of f(7.5) when f(x)=2x+7

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Hey there!!

Given :

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Now, we will need to substitute the value of 7.5 in place of x

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marusya05 [52]

Answer:

$Sin \angle A =0.80$

$Cos \angle A=0.60$

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$Cos \angle B=0.80$

Step-by-step explanation:

Given

I will answer this question using the attached triangle

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In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle A =\frac{BC}{BA}$

Substitute values for BC and BA

$Sin \angle A =\frac{8cm}{10cm}$

$Sin \angle A =\frac{8}{10}$

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$Cos \angle A=\frac{AC}{BA}$

Substitute values for AC and BA

$Cos \angle A=\frac{6cm}{10cm}$

$Cos \angle A=\frac{6}{10}$

$Cos \angle A=0.60$

Solving (b): Sine and Cosine B

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle B =\frac{AC}{BA}$

Substitute values for AC and BA

$Sin \angle B =\frac{6cm}{10cm}$

$Sin \angle B =\frac{6}{10}$

$Sin \angle B =0.60$

$Cos \angle B=\frac{BC}{BA}$

Substitute values for BC and BA

$Cos \angle B=\frac{8cm}{10cm}$

$Cos \angle B=\frac{8}{10}$

$Cos \angle B=0.80$

Using a calculator:

$A = 53^{\circ}$

So:

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$Sin(53^{\circ}) =0.80$ -- approximated

$Cos(53^{\circ}) = 0.6018$

$Cos(53^{\circ}) = 0.60$ -- approximated

$B = 37^{\circ}$

So:

$Sin(37^{\circ}) = 0.6018$

$Sin(37^{\circ}) = 0.60$ --- approximated

$Cos(37^{\circ}) = 0.7986$

$Cos(37^{\circ}) = 0.80$ --- approximated

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3 years ago

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