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zubka84 [21]
3 years ago
10

What is another way to describe an equilateral triangle?

Mathematics
2 answers:
Jlenok [28]3 years ago
4 0
I think the answer is acute
gtnhenbr [62]3 years ago
3 0

I think it a but I sorry if it wrong

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What is the product of (5x + 1)(5x - 1)?
kolezko [41]

Answer:

D) 25x^2-1

Step-by-step explanation:

(5x+1)(5x-1)

25x^2+5x-5x-1

25x^2-1

4 0
3 years ago
For which value of theta is sine theta = negative 1?
Ivan

Answer:

1) 270 degrees

2)  pi/4 rad

Step-by-step explanation:

1.) For which value of theta is sine theta = negative 1?

Given

sintheta = -1

theta = arcsin(-1)

theta = -90degrees

Since sin is negative in the third and 4th quadrant

In the third quadrant, theta = 180 + 90 = 270degrees

In the fourth quadrant, theta = 360 - 90 = 270 degrees

Hence the required value of theta is 270degrees

2) Given the radius of the circle to be 1, the y axis value will also be 1 units

Opposite = 1

adjacent = 1

hyp = √1²+1²

hyp = √2

sin theta = opp/hyp

sin theta = 1/√2

theta = arccsin(1/√2)

theta = 45 degrees

Express in radians

45 degrees = pi/4 radians

Hence the required angle in the first quadrant is pi/4 rad

4 0
3 years ago
Read 2 more answers
Suppose that 13 inches of wire costs 65 cents. At the same rate, how many inches of wire can be bought for 45 cents?
Lina20 [59]
9 because 13/.65 = 20 x .45 = 9
4 0
3 years ago
What two products do you get when you cross-multiply the fractions 2/5 and 3/8?
jarptica [38.1K]
Answer: a. 10 and 12

explanation:
4 0
4 years ago
CORRECT AND CLEAR ANSWER WILL BE GIVEN BRAINLIEST An object of mass 0.30 kg is thrown vertically upwards and reaches a height of
Natalka [10]

Answer:

Final potential energy = 24 Joule

The velocity with which object must be thrown = 4 \sqrt{10} m/s

Step-by-step explanation:

<u>Given:</u>

Mass of object, m = 0.30 Kg

Height of object, h = 8 m

Acceleration due to gravity, g = 10 ms^{-2}

a) Formula for Potential Energy:

E_p =mgh

Where m is the mass of object

g is acceleration due to gravity and

h is the height of object

Putting the values of m, g and h

E_p = 0.3 \times 10 \times 8\\\Rightarrow E_p =24 J

b) Formula for initial and final velocity:

v^{2}   =u^{2} +2gh

where v is the final velocity

u is the initial velocity with which the object is thrown

g is acceleration due to gravity and

h is the height obtained by object

here v = 0 at the height 8 m because it will come to rest at the point it attains the maximum height.

h = 8m

g = -10 ms^{-2} (negative because the object's velocity is decreasing)

Putting the values to find 'u':

0^{2}   =u^{2} +2 \times -10 \times 8\\\Rightarrow u^{2} = 160\\\Rightarrow u = 4 \sqrt{10}\ m/s

7 0
3 years ago
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