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emmasim [6.3K]
3 years ago
15

Write an equation for a line with a slope of 3 and a y-intercept of (0, 2).

Mathematics
1 answer:
DaniilM [7]3 years ago
6 0

Answer:

Step-by-step explanation:

y - 2 = 3(x - 0)

y - 2 = 3x - 0

y = 3x + 2

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Write an equation that is perpendicular to and 3x+y=3 whose y-intercept 5. Anyone please help me, no link just explain how to do
Liula [17]

Answer:

y = \frac{1}{3}x + 5

Step-by-step explanation:

By definition, two lines are perpendicular if and only if their slopes are negative reciprocals of each other:  m = - \frac{1}{m_{2} }, or equivalently, m_{1} * m_{2} = -1.

Given our linear equation  3x + y = 3  (or y = -3x + 3):

We can find the equation of the line (with a y-intercept of 5) that is perpendicular to y = -3x + 3 by determining the negative reciprocal of its slope, -3, which is \frac{1}{3}.

To test whether this is correct, we can take first slope,  m_{1} = -3,  and multiply it with the negative reciprocal slope m_{2} = \frac{1}{3} :

m_{1} * m_{2} = -1

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Therefore, we came up with the correct slope for the other line, which is  \frac{1}{3}.

Finally, the y-intercept is given by (0, 5). Therefore, the equation of the line that is perpendicular to 3x + y = 3 is:

y = \frac{1}{3}x + 5

7 0
3 years ago
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