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nikklg [1K]
3 years ago
6

35 POINTS!!!!!!

Mathematics
1 answer:
mario62 [17]3 years ago
4 0

Answer:

6n+2

Step-by-step explanation:

If n represents the number, the product of 6 and the number is the product of 6 and n: 6n.

When a quantity is "increased by 2" it means 2 has been added to it.

6n "increased by 2" is 6n+2

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Amanda is making pastry dough. She mixes of a 1/3cup of flour and of a 1/5 cup of sugar. If she wants to mix flour and sugar in
mr_godi [17]

Flour : sugar = (1/3) : (1/5) = 5 : 3 . . . . . . . . multiply the first ratio by 15 to eliminate fractions

The total of ratio units in the last representation is 5+3=8, so for a recipe of 16 cups, each ratio unit will stand for 16/8 = 2 cups.

Multiplying the ratio by 2 cups, we find Amanda will need

... 10 cups flour : 6 cups sugar

for her recipe.

4 0
3 years ago
Read 2 more answers
If you set your automobile's cruise control to travel at a speed of 57 miles per hour, how long will it take you (in hours) to d
Sati [7]
3 hours and 45 minutes
6 0
3 years ago
Multiply the polynomials (x + 4)(x + 4)
s2008m [1.1K]

Answer:

x^2 + 8x + 16

Step-by-step explanation:

(x + 4) (x+ 4) multiply x by x and x by 4.

x^2 + 4x

Then multiply 4 by x and 4 by 4.

4x + 16

Then combine like terms.

x^2 + 4x + 4x +16

x^2 + 8x + 16

6 0
3 years ago
Suppose the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65
erma4kov [3.2K]

Answer:

Probability that the sample average is at most 3.00 = 0.98030

Probability that the sample average is between 2.65 and 3.00 = 0.4803

Step-by-step explanation:

We are given that the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65 and standard deviation 0.85.

Also, a random sample of 25 specimens is selected.

Let X bar = Sample average sediment density

The z score probability distribution for sample average is given by;

               Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean = 2.65

           \sigma  = standard deviation = 0.85

            n = sample size = 25

(a) Probability that the sample average sediment density is at most 3.00 is given by = P( X bar <= 3.00)

    P(X bar <= 3) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{3-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z <= 2.06) = 0.98030

(b) Probability that sample average sediment density is between 2.65 and 3.00 is given by = P(2.65 < X bar < 3.00) = P(X bar < 3) - P(X bar <= 2.65)

P(X bar < 3) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{3-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z < 2.06) = 0.98030

 P(X bar <= 2.65) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{2.65-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z <= 0) = 0.5

Therefore, P(2.65 < X bar < 3)  = 0.98030 - 0.5 = 0.4803 .

                                                                             

8 0
3 years ago
Linda had 8 stamps in her collection. She lost 2 stamps. What fraction of the
Alenkinab [10]

Answer:

2/8

Step-by-step explanation:

all the stamps would be 8/8 but she lost 2 therefore giving her 2/8

6 0
3 years ago
Read 2 more answers
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