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postnew [5]
3 years ago
10

A publisher reports that 55% of their readers own a laptop. A marketing executive wants to test the claim that the percentage is

actually different from the reported percentage. A random sample of 280 found that 51% of the readers owned a laptop. Make the decision to reject or fail to reject the null hypothesis at the 0.05 level.
Mathematics
1 answer:
Irina18 [472]3 years ago
6 0

Answer:

We fail to reject the null hypothesis, we accept H₀

Step-by-step explanation:

Population proportion        p₀   =  55 %    p₀   =  0,55

Sample  size         n  =  280

Sample mean     p =  51 %            p =  0,51       q = 0,49

n*p   and  n*q   are both bigger than 10 therefore we can approximate the binomial distribution to a normal distribution

Test  Hypothesis

Null Hypothesis                             H₀                   p   =  p₀

Alternative Hypothesis                Hₐ                    p   ≠  p₀

Significance level is  α  = 0,05    but we have a two-tail test then

α/2  =  0,025

z(c)  =  - 1,96

Computing  z(s)

z(s)  =  ( p - p₀ ) / √(p*q)/n

z(s)  =  ( 0,51 - 0,55 ) / √(0,51*0,49)/280

z(s)  =  - 0,04 * 16,73 / 0,5

z(s)  =  -  1,34

Comparing

z(s)   and z(c)

- 1,34    <    - 1,96

| z(s) | < | z(c)|

Then z(s) is in the acceptance region,  we accept H₀

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Part 1 :
if the number of hours (h) is greater than 7.
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Part 2 :
if she earns 410,
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410 = 210 + (h-7)x 20
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7 0
3 years ago
Write 44 as a product of primes using index notation
trasher [3.6K]

Answer:

Step-by-step explanation:

44 = 2 * 2 * 11

    = 2² *11

3 0
2 years ago
How to find the derivative of cos^2x? i seem to be confused.
slamgirl [31]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2927231

————————

You can actually use either the product rule or the chain rule for this one. Observe:

•  Method I:

y = cos² x

y = cos x · cos x


Differentiate it by applying the product rule:

\mathsf{\dfrac{dy}{dx}=\dfrac{d}{dx}(cos\,x\cdot cos\,x)}\\\\\\&#10;\mathsf{\dfrac{dy}{dx}=\dfrac{d}{dx}(cos\,x)\cdot cos\,x+cos\,x\cdot \dfrac{d}{dx}(cos\,x)}


The derivative of  cos x  is  – sin x. So you have

\mathsf{\dfrac{dy}{dx}=(-sin\,x)\cdot cos\,x+cos\,x\cdot (-sin\,x)}\\\\\\&#10;\mathsf{\dfrac{dy}{dx}=-sin\,x\cdot cos\,x-cos\,x\cdot sin\,x}


\therefore~~\boxed{\begin{array}{c}\mathsf{\dfrac{dy}{dx}=-2\,sin\,x\cdot cos\,x}\end{array}}\qquad\quad\checkmark

—————

•  Method II:

You can also treat  y  as a composite function:

\left\{\!&#10;\begin{array}{l}&#10;\mathsf{y=u^2}\\\\&#10;\mathsf{u=cos\,x}&#10;\end{array}&#10;\right.


and then, differentiate  y  by applying the chain rule:

\mathsf{\dfrac{dy}{dx}=\dfrac{dy}{du}\cdot \dfrac{du}{dx}}\\\\\\&#10;\mathsf{\dfrac{dy}{dx}=\dfrac{d}{du}(u^2)\cdot \dfrac{d}{dx}(cos\,x)}


For that first derivative with respect to  u, just use the power rule, then you have

\mathsf{\dfrac{dy}{dx}=2u^{2-1}\cdot \dfrac{d}{dx}(cos\,x)}\\\\\\&#10;\mathsf{\dfrac{dy}{dx}=2u\cdot (-sin\,x)\qquad\quad (but~~u=cos\,x)}\\\\\\&#10;\mathsf{\dfrac{dy}{dx}=2\,cos\,x\cdot (-sin\,x)}


and then you get the same answer:

\therefore~~\boxed{\begin{array}{c}\mathsf{\dfrac{dy}{dx}=-2\,sin\,x\cdot cos\,x}\end{array}}\qquad\quad\checkmark


I hope this helps. =)


Tags:  <em>derivative chain rule product rule composite function trigonometric trig squared cosine cos differential integral calculus</em>

3 0
3 years ago
What is the value of 5^4 over 5^6
Tasya [4]
5^4
------
5^6
625
-----
15,625
625/15625=25

7 0
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What is an equation of the line that passes through the point ( − 5 , − 3 ) (−5,−3) and is parallel to the line 3 x + 5 y = 15 3
aivan3 [116]

Answer:

would it be 5y

Step-by-step explanation:

6 0
2 years ago
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