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3 years ago

If you have seven dimes how much money do you have

Mathematics

1 answer:

IceJOKER [234]3 years ago

4 0

Answer:

70 cents or 0.70 dollars

Step-by-step explanation:

one dime is 10 cents so if you have 7 than you have 70 cents

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Ashley has 100 books that she wants to give away at the rate of n books per week. Write a recursive function that represents the

enyata [817]

Answer:

f(x) = f(x-1) - n <--- this is the recursive formula

f(0) = 100

f(1) = f(0) - n = 100 - n

f(2) = f(1) - n = 100 - n - n = 100 - 2n

f(3) = f(2) - n = 100 - 2n - n = 100 - 3n

in general the EXPLICIT formula is f(x) = 100 - xn , x=0,1,2,3

Step-by-step explanation:

hope this helps if it is wrong let me know have a blessed day

3 0

2 years ago

Help!! 15 points. Step by step explanation.

Anvisha [2.4K]

Answer: $\bold{f(x)=2\bigg(x+\dfrac{3}{4}\bigg)^2+\dfrac{-25}{8} }$

Step-by-step explanation:

f(x) = 2x² + 3x - 2

$\text{Add 2 to both sides:}\\f(x) + 2 = 2x^2+3x\\\\\\\text{Factor out 2 on the right side:}\\f(x) + 2 = 2\bigg(x^2+\dfrac{3}{2}x\bigg)\\\\\\\text{Add the value that creates a perfect square on the right side:}\\f(x) + 2 + 2\bigg(\dfrac{3}{2\cdot2}\bigg)^2=2\bigg[x^2+\dfrac{3}{2}x+\bigg(\dfrac{3}{2\cdot2}\bigg)^2\bigg]\\\\\\\text{Simplify:}\\f(x)+2+\dfrac{9}{8}=2\bigg(x+\dfrac{3}{4}\bigg)^2\\\\\\\text{Isolate f(x):}\\f(x)=2\bigg(x+\dfrac{3}{4}\bigg)^2+\dfrac{-25}{8}\\$

3 0

3 years ago

Write an equation that is parallel to the line y=-5x+2 and passes through the point (0,3)

Helga [31]

Y=-5x+3 is the answer

3 0

3 years ago

Need help somebody help me plz

Wewaii [24]

Hello,
The formula for finding the circumference of a circle is $2 \pi r$ where r is the radius. SO we can plug 4 in for r in this formula because 4 is the radius: $2 \pi 4=8 \pi$ . We are told to use 3.14 for $\pi$ so we get $8(3.14)=25.12$ . Therefore, the circumference is 25.12 meters.

5 0

3 years ago

Find the Expression OF this equation. c/3 / ac/4 QUESTION C

Fiesta28 [93]

Answer:

See below

Step-by-step explanation:

$(a) \: \: x = \frac{c}{3} \\ \\ \implies \: {x}^{2} = { \bigg( \frac{c}{3} \bigg) }^{2} \\ \\ \bold{\implies \: {x}^{2} = \frac{ {c}^{2} }{9} } \\ \\ (b) \: \: x + y = \frac{c}{3} + \frac{ac}{4} \\ \\\implies \: \bold{x + y = \frac{4c + 3ac}{12} } \\ \\ \frac{xy}{z} = \frac{ \frac{c}{3} \times \frac{ac}{4} }{ \frac{ {a}^{2} }{2c + 1} } \\ \\ = \frac{ \frac{ac ^{2} }{12} }{ \frac{ {a}^{2} }{2c + 1} } \\ \\ = \frac{a {c}^{2} }{12} \times \frac{2c + 1}{ {a}^{2} } \\ \\ \implies\bold{\frac{xy}{z} = \frac{ {c}^{2}(2c + 1) }{12a} }$

8 0

2 years ago