Answer:
children = 177, adults =215
Step-by-step explanation:
im too lazy to write but solve this with a systeme
x(children),y(adults)
x+y=392
x=392-y
2.5y+1.25x=758.75
2.5y+1.25(392-y)=758.75
2.5y+490-1.25y=758.75
490+1.25y=758.75
1.25y=758.75-490
1.25y=268.75
y=268.75/1.25
y=215
x=392-215=177(number of kids)
Answer:
A is your answer
Step-by-step explanation: B is wrong because if it was -6 then it would equal -216
-0.666666 (it’s recurring)
Answer:
The ball will be at 100 feet at time x=0.5 sec and at time x=7.5 sec
Step-by-step explanation:
<u><em>The correct question is</em></u>
A ball is launched upward from a height 40 feet above ground level. the ball's height at t seconds is given by h(t)=-16t^2+128t+40 At what time(s) will the ball be at 100 feet?
we have

so
For h(t)=100 ft
substitute in the equation and solve for x


The formula to solve a quadratic equation of the form
is equal to
in this problem we have

so
substitute in the formula
therefore
The ball will be at 100 feet at time x=0.5 sec and at time x=7.5 sec
If you are given the volume then you can solve
v=volume
h=height
l=legnth
w=width
hlw means h times l times w
v=hlw
so to find height divide both sdie sby lw
v/lw=hlw/lw
v/(lw)=h
so just divide volume by the quantity lengh times width
if you were given the volume