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frosja888 [35]
3 years ago
6

Please answer this correctly

Mathematics
1 answer:
marshall27 [118]3 years ago
6 0

Answer:

hello

Step-by-step explanation:

u sayh-e-l-l-o yW

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Carmen is an engineer making plans to run a rail line, represented by the transversal t, through a city.
lubasha [3.4K]

Answer:

m\angle 1=155\degree

Step-by-step explanation:

The missing diagram is shown in the attachment.

We need to Examine Carmen’s rail plans to identify the measure of ∠1.

Recall that corresponding angles are equal.

From Carmen’s rail plans, the measure of \angle 1  corresponds to 155 degrees because the streets represented by lines V and W are parallel and t is a transversal.

Therefore m\angle 1=155\degree

8 0
3 years ago
Read 2 more answers
What is the standard form of 30+5+2/10
Licemer1 [7]

Combine the terms.

30 + 5 = 35

35 + 2/10 = 35 2/10

35 2/10 is your answer

hope this helps

5 0
4 years ago
David y Angie tienen dos cartulinas iguales. David corta la suya en 3 trozos iguales y Angie la corta en 7 trozos. Los dos usan
Bess [88]

Answer:

(i) David ha empleado \frac{2}{3} de la cartulina.

(ii) Angie ha empleado \frac{2}{7} de la cartulina.

(iii) David ha usado más cartulina.

Step-by-step explanation:

El problema indica que David y Angie emplean una cartulina del mismo tamaño cada uno. David corta la suya en 3 pedazos iguales, mientras que Angie obtiene 7 pedazos iguales. Finalmente, cada uno emplea dos de sus pedazos. A continuación, respondemos a las preguntas del enunciado:

(i) <em>¿Qué fracción de cartulina ha usado David?</em>

La fracción de cartulina empleada por David es igual a los pedazos utilizados divididos por el total de pedazos. Esto es:

x = \frac{2}{3}

David ha empleado \frac{2}{3} de la cartulina.

(ii) <em>¿Qué fracción de cartulina ha usado Angie?</em>

Aplicando el mismo procedimiento del punto anterior, tenemos que:

x = \frac{2}{7}

Angie ha empleado \frac{2}{7} de la cartulina.

(iii) <em>¿Quién ha usado más cartulina?</em>

La persona que ha usado la mayor cantidad de cartulina es aquella que tiene el menor denominador. Por tanto, David ha usado más cartulina.

7 0
3 years ago
A tear in an aircraft hull has a length of 2.3 times 10^-4 inch. The tear becomes 100 times longer. What is the new length of th
Valentin [98]

Answer:

The new length of the tear is 2.3 * 10^-2 inch

Step-by-step explanation:

Here, we are concerned with knowing the new length of the tear.

Originally, the length of the tear is 2.3 * 10^-4 inch.

But this tear became 100 times longer. The new length of the tear will be the old length * 100

Mathematically, that would be 2.3 * 10^-4 inch * 100

= 2.3 * 10^-4 * 10^2

= 2.3 * 10^(-4 + 2)

= 2.3 * 10^-2 inch

8 0
3 years ago
Write the number that comes next in the sequence 4,728 4,818 4,908 please help!!! helpp
Vesnalui [34]

Answer:

4,998

because you add 90 every time that is the difference

3 0
3 years ago
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