-5+d/3=5
d/3-5=5
d-3.5/3=5
d-15/3=5
d-15=15
(d-15)+15=15+15
d-15+15=30
d=30
Hope this helps kiddo
Step-by-step explanation:
The system of equations for eq 1 which is 3x + y = 118 represents the Green High School which filled three buses(with a specific number of students identified as x) and a van(with a specific number of students identified as y) with a total of 118 students.
for eq 2; 4x + 2y = 164; represents Belle High School which filled four buses(with a specific number of students identified as x) and two vans(with a specific number of students identified as y) with a total of 164 students.
The solution represents the specific number of students in the buses and vans in eq1 and eq 2 with x being 36 students and y being 10 students.
substituting 36 for x and 10 for y in eq 1;
3(36) + 10 = 108 + 10 = 118 total students for Green High School
substituting 36 for x and 10 for y in eq2;
4(36) + 2(10) = 144 + 20 = 164 total students for Belle High school
To solve for <em>x</em>, we must first isolate the term containing <em>x</em> which in this problem is 5x.
Since 10 is being added to 5x, we subtract 10 from both sides of the equation to isolate the 5x.
On the left, the +10 and -10 cancel out and on the right, 20 - 10 is 10 and we have 5x = 10.
Now we can finish things off by just dividing both sides of the equation by 5. On the left the 5's cancel and on the right, 10 divided by 5 is 2 so <em>x = 2</em>.
