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2 years ago

GIVING BRAINLIEST!!!!!!!

Mathematics

1 answer:

Len [333]2 years ago

5 0

First find the smallest value
You would need the smallest y value and the greatest x value
y = 10, x = 7
Therefore 10/7 would be the smallest
Now find the greatest
You would need the largest y value and the smallest x value
Y = 12, x = 6
Therefore 12/6 or 2 would be the largest
Solution: 10/7 < y/x < 2

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Here is a square inscribed in a circle with radius 1 meter. What is the perimeter of

Dimas [21]

Answer:

$4\sqrt{2}$

Step-by-step explanation:

distance formula: $\sqrt{\left(x_2-x_1\right)^{2}+\left(y_2-y_1\right)^{2}}$

set square to be centered on the origin and find the distance between 2 of the connected points

$\sqrt{\left(3-2\right)^{2}+\left(2-1\right)^{2}}$

= $\sqrt{\left(1\right)^{2}+\left(1\right)^{2}}$

= $\sqrt{2}$

multiply by 4 as it is a square and all of its sides are equal

$4\sqrt{2}$

insert units

$4\sqrt{2}\ \ meters$

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2 years ago

What is the input value other than 0 for which f(x)=−2

balu736 [363]

Answer:

Its 5

Step-by-step explanation:

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3 years ago

What is the equation of the graph below? On a coordinate plane, a curve crosses the y-axis at y = 1. It has a maximum of 1 and a

Andreas93 [3]

The equation of the graph is given by y = cos(0.4x) and has an amplitude of 1

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Since the curve crosses the y-axis at y = 1, hence it is a cosine graph. It has a maximum of 1 and a minimum of negative 1, therefore the amplitude is 1

Also, the angular frequency = 2π * 1/5π = 0.4

The equation of the graph is given by y = cos(0.4x) and has an amplitude of 1

Find out more on equation at: brainly.com/question/2972832

#SPJ1

7 0

1 year ago

I need a riddle with this number 5109

dezoksy [38]

You get this number when multiplying the numbers of 1703 and 3

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3 years ago

Solve for x, 0 ≤ x ≤2π (2cosx-1)(2sinx+√3 ) = 0

vladimir1956 [14]

Answer:

x = π/3, x = 5π/3, x = 4π/3

Step-by-step explanation:

Let's split the given equation (2cosx-1)(2sinx+√3 ) = 0 into two parts, and solve each separately. These parts would be 2cos(x) - 1 = 0, and 2sin(x) + √3 = 0.

$2\cos \left(x\right)-1=0,\\2\cos \left(x\right)=1,\\\cos \left(x\right)=\frac{1}{2}$

Remember that the general solutions for cos(x) = 1/2 are x = π/3 + 2πn and x = 5π/3 + 2πn. In this case we are given the interval 0 ≤ x ≤2π, and therefore x = π/3, and x = 5π/3.

Similarly:

$\:2\sin \left(x\right)+\sqrt{3}=0,\\2\sin \left(x\right)=-\sqrt{3},\\\sin \left(x\right)=-\frac{\sqrt{3}}{2}$

The general solutions for sin(x) = - √3/2 are x = 4π/3 + 2πn and x = 5π/3 + 2πn. Therefore x = 4π/3 and x = 5π/3 in this case.

So we have x = π/3, x = 5π/3, and x = 4π/3 as our solutions.

5 0

3 years ago