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Effectus [21]
3 years ago
10

Find an equation of the line parallel to the line 3x + 6y = 5 and passing through the point (1 , 3). Write the equation in the s

lope intercept form.
Mathematics
1 answer:
Nina [5.8K]3 years ago
3 0

Answer:

I think that would be 3x+6y=21 sorry if I am wrong

Step-by-step explanation:

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What is the answer for 3r=10+5 when r=10
katen-ka-za [31]

Answer:

Step-by-step explanation:

What is the VALUE OF 3r=10+5 when r=10?

substitute 10 for r in 3r=10+5.  We get:

3(10) = 10 + 5, or 30 = 15.  This equation is FALSE when r = 10.

You could solve the equation for r, however:

3r=10+5 becomes 3r = 15, and so r = 5.  5 is a solution; 10 is not a solution.

6 0
3 years ago
-3/4*2/5 what is that answer to this
rosijanka [135]

Answer:

Step-by-step explanation:

-3/4 * 2/5 = fraction multiplication.

-6/20 = -3/10

6 0
3 years ago
Determine the zeros of the function <br> 5) y=-x² + 2x + 1
Rus_ich [418]
<h3>Zeros of function are x = 1 + \sqrt{2} \text{ and } x = 1 - \sqrt{2}</h3>

<em><u>Solution:</u></em>

<em><u>We have to find the zeros of the function</u></em>

y = -x^2 + 2x+1

Find the zeros of function:

-x^2 + 2x+1 = 0\\\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=-1,\:b=2,\:c=1\\\\x  =\frac{-2\pm \sqrt{2^2-4\left(-1\right)1}}{2\left(-1\right)}

Simplify\\\\x=\frac{-2 \pm \sqrt{4+4}}{-2}\\\\x =\frac{-2 \pm \sqrt{8}}{-2}\\\\Simplify\\\\x =\frac{-2 \pm 2 \sqrt{2}}{-2}\\\\x = 1 \pm \sqrt{2}

We have two zeros

x = 1 + \sqrt{2} \text{ and } x = 1 - \sqrt{2}

Thus zeros of function are x = 1 + \sqrt{2} \text{ and } x = 1 - \sqrt{2}

3 0
3 years ago
Read 2 more answers
Complete the proof!!!
Tamiku [17]

Answer:

The correct options are;

1. Definition of supplementary angles

2. m∠1 + m∠2 = m∠1 + m∠3

3. m∠2 = m∠3

4. Definition of congruent angles

Step-by-step explanation:

The two column proof is presented as follows;

Statement    {}                                      Reason

1. ∠1 and ∠2 are supplementary {}       Given

∠1 and ∠3 are supplementary {}      

2. m∠1 + m∠2 = 180°     {}                      (1) Definition of supplementary angles

m∠1 + m∠3 = 180°

3. (2) m∠1 + m∠2 = m∠1 + m∠3      {}     Transitive Property

4. (3) m∠2 = m∠3     {}                            Subtraction property of equality

5. ∠2 ≅ ∠3     {}                                       (4) Definition of congruent angles

Given that angles ∠1 and ∠2 are supplementary, we have, ∠1 + ∠2 = 180°

Given that angles ∠1 and ∠3 are also supplementary, we also have, ∠1 + ∠3 = 180°

∴ ∠1 + ∠2 = 180° = ∠1 + ∠3

∠1 + ∠2 = ∠1 + ∠3

∠1 + ∠2 - ∠1 = ∠1 + ∠3 - ∠1

∴ ∠2 = ∠3

∴ ∠2 ≅ ∠3, by definition of congruent angles.

4 0
3 years ago
Subtract -5/18 - (-1/4)
Fudgin [204]
You would have to convert subtraction to addition. so it would be -5/18 + 1/4.

-5/18+1/4 is -0.028 rounded up
4 0
3 years ago
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