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VladimirAG [237]
3 years ago
5

Using a calculator, work out: V2704 * 2^2– V49

Mathematics
1 answer:
Bond [772]3 years ago
5 0

Answer:

201

Step-by-step explanation:

The computation is shown below:

Given that

= \sqrt{2704} \times 2^2 - \sqrt{49}

= 52 × 4 - 7

= 208 - 7

= 201

Here we assume that V denotes the square so according to this we solve the given situation

After solving this, the answer is 201

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A veterinarian’s assistant made a table that shows the animals seen in the office in one week. What is the probability that the
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Answer:

The probability that the pet seen was sick is 53.57%.

Step-by-step explanation:

The probability of an event <em>E</em> is the ration of the number of favorable outcomes to the total number of outcomes.

P(E)=\frac{n(E)}{N}

Here,

n (E) = number of favorable outcomes

N = total number of outcomes

Denote the events as follows:

<em>C</em> = the pet is a cat

<em>D</em> = the pet is a dog

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<em>S</em> = the pet is sick.

The data provided is summarized as follows:

n (C) = 28

n (C ∩ S) = 3

n (D) = 42

n (B ∩ S) = 4

n (O) = 24

n (O ∩ S) = 8

Compute the probability that a cat was sick as follows:

P(C\cap S)=\frac{n(C\cap S)}{n(C)}=\frac{3}{28}

Compute the probability that a dog was sick as follows:

P(D\cap S)=\frac{n(D\cap S)}{n(D)}=\frac{4}{42}=\frac{2}{21}

Compute the probability that another animal was sick as follows:

P(O\cap S)=\frac{n(O\cap S)}{n(O)}=\frac{8}{24}=\frac{1}{3}

Compute the probability that the pet seen was sick as follows:

P (S) = P (C ∩ S) + P (D ∩ S) + P (O ∩ S)

       =\frac{3}{28}+\frac{2}{21}+\frac{1}{3}\\=\frac{9+8+28}{84}\\=\frac{45}{84}\\=0.5357

Thus, the probability that the pet seen was sick is 53.57%.

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