Answer: if Gregory draws the segment with endpoints A and A’, then the midpoint will lie on the line of reflection.
Explanation:
Given that a triangle ABC is reflected in triangle A'B'C'
Here reflection is done on a line
If you imagine the line as a mirror then ABC will have image on the mirror line as A'B'C'
Recall that in a mirror the object and image would be equidistant from the mirror and also the line joining the image and object would be perpendicular to the mirror
But note that corresponding images will only be perpendicular bisector to the line
So A and A' only will be corresponding so AA' will have mid point on line
Option 1 is right
Answer:<span> =<span><span><span><span><span>x4</span>+<span>15<span>x3</span></span></span>−<span>77<span>x2</span></span></span>+<span>14x</span></span>−<span>40</span></span></span>
Answer:
(x, y) = (-4, 15)
Step-by-step explanation:
The two equations have the same coefficient for y, so you can eliminate y by subtracting one equation from the other. Here the x coefficient is largest for the first equation, so it will work best to subtract the second equation.
(3x +y) -(2x +y) = (3) -(7)
x = -4 . . . . . . . . simplify
Now, we can find y by substituting this value for x.
2(-4) +y = 7
y = 7 +8 = 15 . . . . . add 8 to both sides of the equation
The solution is (x, y) = (-4, 15).
Answer:
it would be in the 100eds place
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
From the given coordinates
A(6, 0), B(0, 0) then AB = 6 - 0 = 6
B(0, 0), C(0, 8) then BC = 8 - 0 = 8
To calculate AC use Pythagoras' theorem on the right triangle formed
AC² = AB² + BC² = 6² + 8² = 36 + 64 = 100
Take the square root of both sides, hence
AC = 
= 10
Perimeter = AB + BC + AC = 6 + 8 + 10 = 24 → C
