Answer:
(a) 2 degree celsius per hour
(b) 3 degree celsius per hour.
Step-by-step explanation:
From the question,
(a) Avearge rate of rise in temperature per hour(T') = Rise in temperature(T)/Time required for the rise(t).
T' = T/t.................... Euqation 1
Rise in temperature (T) = 4 degree celsius, t = 10.00 am to noon = 2 hours.
Substitute into equation 1
T' = 4/2
T' = 2 degree celsius per hour.
(b) Also,
Average rate of fall in temperature per hour (T') = Fall in temperature (T)/Time(t)
T' = T/t
Given: T = 6 degree celsius, t = 3:00 pm to 5:00 pm = 2 hours
T' = 6/2
T' = 3 degree celsius per hour
Determining a car's depreciation over a ten year period is considered a bivariate.
<h3>What is a bivariate?</h3>
A Bivariate data is made up of two variables that are observed against each other. In determining the deprecation of a car, the cost of the car is observed against the passage of time and the depreciation factor.
To learn more about depreciation, please check: brainly.com/question/25552427
#SPJ1
Answer:
530
Step-by-step explanation:
200+6(55)
6x55=330
200+330=530
Answer: theres a website called weegy did you try that?
Answer:
your answer should be 15%
