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luda_lava [24]
3 years ago
8

What is the equation of the following graph in vertex form?

Mathematics
2 answers:
Elza [17]3 years ago
6 0
\bf \boxed{y=(x-{{ h}})^2+{{ k}}}\\\\
x=(y-{{ k}})^2+{{ h}}\qquad\qquad  vertex\ ({{ h}},{{ k}})\\\\
-----------------------------\\\\
\textit{vertex is at 4,-4}\implies 
\begin{cases}
h=4\\
k=-4
\end{cases}\implies y=(x-4)^2+(-4)
\\\\\\
\boxed{y=(x-4)^2-4}
nalin [4]3 years ago
3 0
For
y=a(x-h)²+k
vertex is (h,k)

so

the vertex is (4,-4)
so
y=a(x-4)²-4
find a
we see the point
(0,12)
sub 0 for x and 12 for y and solve for a
12=a(0-4)²-4
12=a(-4)²-4
12=16a-4
add 4 both sides
16=16a
1=a


equation is
y=1(x-4)²-4 or
y=(x-4)²-4

A is answer
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