Sample Space ={5 Red, 8White, 2 Blacks} = 15 possible outcomes.
Favorable outcomes={5 Red}
1) P(drawing 1st Red) = 5/15
2) P(drawing ANOTHER RED) = 4/14 (because one Red already drawn and NOT replaced, so the remaining Red are now 4 and the new sample space is now 14, since 1 red already drawn), Hence
P( 1 Red AND another Red) = (5/15).(4/15) or:
"5 over 15 multiplied by 4 over 14"
The correct way to write this equation is .25x-3=12. The .25 is interchangeable with
Answer:
x=-224/229,
y=296/229,
z=118/229
Step-by-step explanation:
-5x-7y-4z=-6
6x+2y+3z=-2
-x+2y-7z=0...........( multiple with (-5) and sum with 1st equation, mult with 6 and sum with 2nd equation)
______________
-x+2y-7z=0
-17y+31z=-6.....(mult with 14)
14y-39z=-2.....(mult with -17) then sum
___________
-x+2y-7z=0
-229z=-118, so here we have z=118/229.
14y-39*(118/229)=-2, from here we have y=296/229
-x+2*(296/229)-7*(118/229)=0, we get that x=-234/229
In the same way you can do this in the matrix form>>
Answer:
2
Step-by-step explanation:
hope it helps god blessss