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2 years ago

Erica solved the equation −5x − 25 = 78; her work is shown below. Identify the error and where it was made.

Mathematics

1 answer:

Romashka-Z-Leto [24]2 years ago

8 0

In step one, you are supposed to add 25 to both sides, because if you just subtract, it would be -5x-50=53

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Someone please help and explain it would really help

Vaselesa [24]

So when you're solving for x here and distribute 8 on the right side, it would look like this:

$8x+47=8(x+5)\\ \\ 8x+47=8x+40$

Now in order to solve for x, we know we have to get all the x's on one side of the equal sign. Let's get all our x's to the left side. Since the right side has a positive 8x, you need to subtract 8x on the right. But whatever you do to one side you must do to the other. So since we are subtracting 8x on the right, we need to do that on the left.

But we can't! Since both sides will cancel out to zero before x can be solved.

Therefore the answer is 0.

Hope that helps!

8 0

3 years ago

I need the answer ASAP

iVinArrow [24]

Answer:

Step-by-step explanation:

When squaring the number 5 (i.e $5^2$ ) the answer is 25. $5^{2}$ is the same thing as 5 times 5. Basically with the square root, you are going backwards, so you are therefore finding the base of it all.

7 0

3 years ago

Read 2 more answers

Let g(x)=Intragal from 0 to x f(t) dt, where r is the function whos graph is shown.

leonid [27]

$\displaystyle g(x) = \int_0^x f(t) \, dt$

then g(x) gives the signed area under f(x) over a given interval starting at 0.

In particular,

$\displaystyle g(0) = \int_0^0 f(t) \, dt = 0$

since the integral of any function over a single point is zero;

$\displaystyle g(4) = \int_0^4 f(t) \, dt = 8$

since the area under f(x) over the interval [0, 4] is a right triangle with length and height 4, hence area 1/2 • 4 • 4 = 8;

$\displaystyle g(8) = \int_0^8 f(t) \, dt = 0$

since the area over [4, 8] is the same as the area over [0, 4], but on the opposite side of the t-axis;

$\displaystyle g(12) = \int_0^{12} f(t) \, dt = -8$

since the area over [8, 12] is the same as over [4, 8], but doesn't get canceled;

$\displaystyle g(16) = \int_0^{16} f(t) \, dt = 0$

since the area over [12, 16] is the same as over [0, 4], and all together these four triangle areas cancel to zero;

$\displaystyle g(20) = \int_0^{20} f(t) \, dt = 24$

since the area over [16, 20] is a trapezoid with "bases" 4 and 8, and "height" 4, hence area (4 + 8)/2 • 4 = 24;

$\displaystyle g(24) = \int_0^{24} f(t) \, dt = 64$

since the area over [20, 24] is yet another trapezoid, but with bases 8 and 12, and height 4, hence area (8 + 12)/2 • 4 = 40, which we add to the previous area.

5 0

2 years ago

Find the area of the composite figure below.

pashok25 [27]

Answer: D is the correct answer.

8 0

2 years ago

Convert 1/2 yard in inches

Tom [10]

1/2 yard =18 inches

(multiply value by 36)

8 0

2 years ago