All categories

4 years ago

Simplify the ratio: 28:35

Mathematics

2 answers:

Dovator [93]4 years ago

6 0

Both can be divided by 7

28/7= 4

35/7= 5

4:5

Mama L [17]4 years ago

3 0

28:35
Those are divisible by 7 so divide both sides by seven
the answer is 4:5

You might be interested in

Solve the problem. A retired couple has $120,000 to invest to obtain annual income. They want some of it invested in safe Certif

Nataly [62]

ertificates 6.00% per annum ---x

AA bond 11.00% per annum ---y

x + 1 y= 160000 ------------------------1

6.00% x + 11.00% y= 15600

Multiply by 100

6 x + 11 y= 1560000.00 --------2

Multiply (1) by -6

we get

-6 x -6 y= -960000.00

4 0

3 years ago

How to write the sum of the number as the product of their GCF of 56+64

Ghella [55]

GCF(56; 64) = 8

56 = 8 · 7
64 = 8 · 8

56 + 64 = 8 · 7 + 8 · 8 = 8·(7 + 8)

Used distributive property: a(b + c) = ab + ac

3 0

4 years ago

Find the area of a regular pentagon with an apothem of 11 units. *

docker41 [41]

Answer:

<h2>440 square units</h2>

Step-by-step explanation:

We can find half of a side of the pentagon with the expression

$tan(36\°)=\frac{s_{half} }{11}$

Because, as a regular polygon, all its sectors have the same central angle, and the apothem divides equally each sector in two equal parts.

$s_{half} \approx 8$

Therefore, half of a side is 8 units long, which means each side measures 16 units.

Now, the area of a penthagon is defined by

$A=\frac{p \times a}{2}$

Where $p$ is the perimeter and $a$ is the apothem. Where the perimeter is the sum of all sides, which is 80 units.

$A= \frac{80 \times 11}{2} =440 \ u^{2}$

Therefore, the right answer is the second choice.

3 0

3 years ago

Let A = {1, 2, 3, 4}, B = {3, 4, 5, 6}, and C = {5, 6, 7, 8}. Find each of the following sets. (Enter your answers in set-roster

cluponka [151]

Answer:

(a) {1, 2, 5, 6}

(b) {3, 4, 7, 8}

(c) {1, 2, 3, 4, 5, 6, 7, 8}

(d) {1, 2, 7, 8}

Step-by-step explanation:

Given sets,

A = {1, 2, 3, 4}, B = {3, 4, 5, 6} and C = {5, 6, 7, 8},

(a) Since, A Δ B = (A\B)∪(B\A) = all elements of A\B and B\A

∵ A\B = elements of set A which are not in B

= {1, 2}

And, B\A = {5, 6}

So, A Δ B = {1, 2, 5, 6}

(b) B\C = {3, 4},

C\B = {7, 8}

⇒ B Δ C = (B\C)∪(C\B) = {3, 4, 7, 8}

(c) A\C = {1, 2, 3, 4},

C\A = {5, 6, 7, 8},

⇒ A Δ C = (A\C)∪(C\A) = {1, 2, 3, 4, 5, 6, 7, 8}

(d) (A Δ B)\C = {1, 2}

C\(A Δ B) = {7, 8}

A Δ C = ((A Δ B)\C)∪(C\(A Δ B)) = {1, 2, 7, 8}

7 0

4 years ago

PLEASE HELP ASAP!! ALGEBRA! PICTURE BELOW!

zubka84 [21]

Answer:

(y+2)=3/4(x+6) or (y-4)=3/4(x-2)

Step-by-step explanation:

Point-slope form : (y-y1)=m(x-x1)

slope = m =(y2 - y1)/(x2 -x1)

Point 1 (-6,-2), so x1= - 6, y1= -2

Point 2 (2, 4), so x2 = 2, y2 = 4

m=(4-(-2))/(2-(-6)) = 6/8 = 3/4

Point-slope form : (y-y1)=3/4(x-x1)

We can use any point. If we use point 1 we get

Point-slope form : (y+2)=3/4(x+6).

If we use point 2 we get

(y-4)=3/4(x-2)

5 0

4 years ago