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aivan3 [116]
4 years ago
12

Who can help me ?????

Mathematics
2 answers:
klio [65]4 years ago
8 0
The answer should be 3.
andriy [413]4 years ago
8 0
The answer should be 2
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Refer to scenario 4. assume that the profit equation is $110x1 + $150x2 what is the profit at corner point (0, 30)?
SashulF [63]
If you have the profit formula which is profit (x1, x2) = 110x1 + 150x2, then by substitution of the given point (x1, x2) = (0, 30), you can find the profit at the corner point profit (0.30 ) = 110 (0) + 150 (30) = 4500.Therefore the profit will be $ 4500
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4 years ago
How to solve function operations
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3 0
3 years ago
How do I find out how to work out , y=mx+c ???
hjlf
Y=mx+c isn't an equation to solve. It's the slope-intercept formula for graphing lines.
y and x are the variables, and m and c are the constants.
As an example, the line y=4x+2 looks like this:

3 0
3 years ago
Read 2 more answers
- 1/5[y+x]<br> whats the answer
stiv31 [10]

Answer:

i aint never seen 2 pretty best friends always one of them gotta be ugly....

Step-by-step explanation:

4 0
3 years ago
Can anyone help me solve this.I need proper equation..Thanks​
artcher [175]

Answer:

y = 9\sqrt{2}

Step-by-step explanation:

Using the sine ratio in the right triangle and the exact value

sin45° = \frac{1}{\sqrt{2} }

sin45° = \frac{opposite}{hypotenuse} = \frac{9}{y}

Multiply both sides by y

y × sin45° = 9, that is

y × \frac{1}{\sqrt{2} } = 9

Multiply both sides by \sqrt{2}

y = 9\sqrt{2}

3 0
4 years ago
Read 2 more answers
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