Ask question

Ask question

All categories

3 years ago

7

Pls provide an explanation if possible

2 answers:

Sauron [17]3 years ago

6 0

It is a trick question it says all the stuff about how much they collected to distract you actually your dividing the money they won in half so 300 600 divided by 2 is 300

mote1985 [20]3 years ago

4 0

Answer:

6661 divided by 2

Step-by-step explanation:

idrk

You might be interested in

40 POINTS AVAILABLE!!!<br> PLEASE HELP

NemiM [27]

Step-by-step explanation:

$\begin{array}{ccc}1&-&d\\2&-&c\\3&-&a\\4&-&b\\5&-&f\\6&-&e\end{array}$

Value 1:

r = 5ft, h = 10ft. Substitute:

$SA=2\pi(5)(10)+2\pi(5^2)=100\pi+50\pi=150\pi\ ft^2$

Value 2:

r = 2in, h = 4in. Substitute:

$V=\dfrac{1}{3}\pi(2^2)(4)=\dfrac{1}{3}\pi(4)(4)=\dfrac{16\pi}{3}\\\\\pi\approzx3.14\to V\approx\dfrac{(16)(3.14)}{3}\approx16.75\ in^3$

Value 3:

r = 6m. Substitute:

$V=\dfrac{4}{3}\pi(6^3)=\dfrac{4}{3}\pi(216)=4\pi(72)=288\pi\ m^3\\\\\pi\approx3.14\to V\approx288(3.14)=904.32\ m^3$

3 0

3 years ago

Read 2 more answers

Can someone Please Help meh‍

astra-53 [7]

Answer: the one for 3b (8) + (-2)(7c) ; for b= 2, c= 3 is

6

Step-by-step explanation:

3b(8)+(-2)(7c)

3(2)(8)+(-2)(7)(3)

(6)(8)+(-14)(3)

48-42

6

8 0

3 years ago

Read 2 more answers

the distance between two towns is 75 km. the distance between two towns on a map is i.5 cm. what is the scale on the map?

Temka [501]

Easy 75km / 5 cm = 15km:1 cm
hope this helps....

5 0

3 years ago

Read 2 more answers

How can u find the perimeter in a graph

frozen [14]

Yeah you should try khan academy or Ytube

7 0

3 years ago

For the given term, find the binomial raised to the power, whose expansion it came from: 15(5)^2 (-1/2 x) ^4

Elina [12.6K]

Answer:

<em>C.</em> $(5-\frac{1}{2})^6$

Step-by-step explanation:

Given

$15(5)^2(-\frac{1}{2})^4$

Required

Determine which binomial expansion it came from

The first step is to add the powers of he expression in brackets;

$Sum = 2 + 4$

$Sum = 6$

Each term of a binomial expansion are always of the form:

$(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......$

Where n = the sum above

$n = 6$

Compare $15(5)^2(-\frac{1}{2})^4$ to the above general form of binomial expansion

$(a+b)^n = ......+15(5)^2(-\frac{1}{2})^4+.......$

Substitute 6 for n

$(a+b)^6 = ......+15(5)^2(-\frac{1}{2})^4+.......$

[Next is to solve for a and b]

<em>From the above expression, the power of (5) is 2</em>

<em>Express 2 as 6 - 4</em>

$(a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......$

By direct comparison of

$(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......$

and

$(a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......$

We have;

$^nC_ra^{n-r}b^r= 15(5)^{6-4}(-\frac{1}{2})^4$

Further comparison gives

$^nC_r = 15$

$a^{n-r} =(5)^{6-4}$

$b^r= (-\frac{1}{2})^4$

[Solving for a]

By direct comparison of $a^{n-r} =(5)^{6-4}$

$a = 5$

$n = 6$

$r = 4$

[Solving for b]

By direct comparison of $b^r= (-\frac{1}{2})^4$

$r = 4$

$b = \frac{-1}{2}$

Substitute values for a, b, n and r in

$(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......$

$(5+\frac{-1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......$

Solve for $^6C_4$

$(5-\frac{1}{2})^6 = ......+ \frac{6!}{(6-4)!4!)}*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+ \frac{6!}{2!!4!}*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+ \frac{6*5*4!}{2*1*!4!}*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+ \frac{6*5}{2*1}*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+ \frac{30}{2}*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+15*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+15(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+15(5)^2(\frac{-1}{2})^4+.......$

<em>Check the list of options for the expression on the left hand side</em>

<em>The correct answer is </em> $(5-\frac{1}{2})^6$ <em />

3 0

3 years ago