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Rzqust [24]
3 years ago
9

Construct a histogram for the following data set: 11, 17, 13, 2, 22, 18, 16, 14, 16, 21, 17, 9, 9, 7, 3

Mathematics
2 answers:
Vera_Pavlovna [14]3 years ago
6 0

Answer:

17

Step-by-step explanation:

i did this so many times in middle school

Rashid [163]3 years ago
3 0

Answer:

subject?

Step-by-step explanation:

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Find s(2t - 4) for s(t) = 3t - 7 <br> A)6t - 19 B) 6t - 18 C) 5t - 11 D) 5t - 19
asambeis [7]
Hello,

Answer A

s(x)=3x-7
s(2t-4)=3*(2t-4)-7=6t-12-7=6t-19
3 0
3 years ago
What is the complete factorization of the polynomial below x^3+2x^2+4x+8
vagabundo [1.1K]

Answer:

c) (x + 2)(x + 2i)(x - 2i)

Step-by-step explanation:

x^3 + 2x^2 + 4x + 8

= (x^3 + 2x^2) + (4x + 8)

= x^2( x + 2) + 4(x + 2)

= (x + 2)(x^2 + 4)

= (x + 2)(x^2 - 4i^2)  ---------------------------->(i^2 = -1)

= (x + 2)(x + 2i)(x - 2i)

3 0
3 years ago
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Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and
zloy xaker [14]

Answer:

(0,0)   (4000,0) and (500,79)

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW

\frac{dW}{dt} = -0.02W + 0.00004RW

To solve this, we first equate \frac{dR}{dt} and \frac{dW}{dt} to 0.

So, we have:

0.09R(1 - 0.00025R) - 0.001RW = 0

-0.02W + 0.00004RW = 0

Factor out R in 0.09R(1 - 0.00025R) - 0.001RW = 0

R(0.09(1 - 0.00025R) - 0.001W) = 0

Split

R = 0   or 0.09(1 - 0.00025R) - 0.001W = 0

R = 0   or  0.09 - 2.25 * 10^{-5}R - 0.001W = 0

Factor out W in -0.02W + 0.00004RW = 0

W(-0.02 + 0.00004R) = 0

Split

W = 0 or -0.02 + 0.00004R = 0

Solve for R

-0.02 + 0.00004R = 0

0.00004R = 0.02

Make R the subject

R = \frac{0.02}{0.00004}

R = 500

When R = 500, we have:

0.09 - 2.25 * 10^{-5}R - 0.001W = 0

0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0

0.09 -0.01125 - 0.001W = 0

0.07875 - 0.001W = 0

Collect like terms

- 0.001W = -0.07875

Solve for W

W = \frac{-0.07875}{ - 0.001}

W = 78.75

W \approx 79

(R,W) \to (500,79)

When W = 0, we have:

0.09 - 2.25 * 10^{-5}R - 0.001W = 0

0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0

0.09 - 2.25 * 10^{-5}R = 0

Collect like terms

- 2.25 * 10^{-5}R = -0.09

Solve for R

R = \frac{-0.09}{- 2.25 * 10^{-5}}

R = 4000

So, we have:

(R,W) \to (4000,0)

When R =0, we have:

-0.02W + 0.00004RW = 0

-0.02W + 0.00004W*0 = 0

-0.02W + 0 = 0

-0.02W = 0

W=0

So, we have:

(R,W) \to (0,0)

Hence, the points of equilibrium are:

(0,0)   (4000,0) and (500,79)

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