When factored completely, what are the factors of 4x^2-16 ?

Mathematics

2 answers:

Semmy [17]3 years ago

8 0

$Use:a^2-b^2=(a-b)(a+b)\\\\4x^2-16=4(x^2-4)=4(x^2-2^2)=\boxed{4(x-2)(x+2)}$

Klio2033 [76]3 years ago

8 0

$4x^2-16=\\
4(x^2-4)=\\
4(x-2)(x+2)$

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