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shepuryov [24]
3 years ago
7

When factored completely, what are the factors of 4x^2-16 ?

Mathematics
2 answers:
Semmy [17]3 years ago
8 0
Use:a^2-b^2=(a-b)(a+b)\\\\4x^2-16=4(x^2-4)=4(x^2-2^2)=\boxed{4(x-2)(x+2)}
Klio2033 [76]3 years ago
8 0
4x^2-16=\\
4(x^2-4)=\\
4(x-2)(x+2)
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