Answer:
x = 1 or x = -4 or x = -6 thus d: is your answer
Step-by-step explanation:
Solve for x over the real numbers:
x^3 + 9 x^2 + 14 x - 24 = 0
The left hand side factors into a product with three terms:
(x - 1) (x + 4) (x + 6) = 0
Split into three equations:
x - 1 = 0 or x + 4 = 0 or x + 6 = 0
Add 1 to both sides:
x = 1 or x + 4 = 0 or x + 6 = 0
Subtract 4 from both sides:
x = 1 or x = -4 or x + 6 = 0
Subtract 6 from both sides:
Answer: x = 1 or x = -4 or x = -6
Answer:
Step-by-step explanation:
Answer:
see explanation
Step-by-step explanation:
(a)
Given
2k - 6k² + 4k³ ← factor out 2k from each term
= 2k(1 - 3k + 2k²)
To factor the quadratic
Consider the factors of the product of the constant term ( 1) and the coefficient of the k² term (+ 2) which sum to give the coefficient of the k- term (- 3)
The factors are - 1 and - 2
Use these factors to split the k- term
1 - k - 2k + 2k² ( factor the first/second and third/fourth terms )
1(1 - k) - 2k(1 - k) ← factor out (1 - k) from each term
= (1 - k)(1 - 2k)
1 - 3k + 2k² = (1 - k)(1 - 2k) and
2k - 6k² + 4k³ = 2k(1 - k)(1 - 2k)
(b)
Given
2ax - 4ay + 3bx - 6by ( factor the first/second and third/fourth terms )
= 2a(x - 2y) + 3b(x - 2y) ← factor out (x - 2y) from each term
= (x - 2y)(2a + 3b)
No it isn't.
Explanation:
x/y * y = (y-6) * y
x = y^2 - 6y
A function gives just one y for every x
In this case there will always be 2 y's for every x
Example:
y can be
y = 6
or
y =−6
(0,-6) & (0,6)
Answer:
i dont understand?
Step-by-step explanation:
