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2 years ago

Find the value of x. Give your answer in simplest radical form.

Mathematics

1 answer:

yarga [219]2 years ago

8 0

Using the pythagoras theorem for a right-angled triangle:-

x^2 = 13*2 - 9^2 = 88

x = sqrt 88 = 2 sqrt 22

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Express the sum of 3x^2+5x-6 and -x^2+3×+9?

djverab [1.8K]

I hope this helps you

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3 years ago

Triangle GHI is translated using the rule (x, y) → (x + 5, y) to create triangle G′H′I′. If a line segment is drawn from point G

Debora [2.8K]

Step-by-step explanation:

the second answer.

they are parallel and congruent (same length).

simply because both points were translated by adding the same number of units to x. so, they have the same length, and point in the same direction.

6 0

1 year ago

What is the domain of the sine and cosine functions?

eimsori [14]

Answer:

domain of the sine and cosine functions is all real numbers

Step-by-step explanation:

range of both the sine and cosine functions is [−1,1]

graph can go left and right to infinity

graph goes up and down between 1 and -1

graph looks like a wave or

like U letters next to each other

UUUU

sine and cosine of an angle have the same absolute value as the sine and cosine of its reference angle.

mathlibretextsorg

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1 year ago

The price of a video game system dropped by 18%. What is the current price if it used to be $140?

IgorC [24]

Answer:

$114.80

Step-by-step explanation:

Multiply 18% and 140 to find the drop price.

.18 x 140= $25.20 now subtr. this from the original price

$140.00-$25.20=$114.80 is the sale price

4 0

2 years ago

The number of girl child per family was recorded for 1000 families with 3 children. The data obtained was as follows: [2] Number

ira [324]

Answer:

$a.\ Probability = 0.426$

$b.\ Probability = 0.574$

Step-by-step explanation:

Given

$Total\ Families = 1000$

Number of Girls : 0 ----> 1 -----> 2 ------->3

Number of Families: 112 -> 314 --> 382 ---> 192

Solving (a): At most one girl

From the table, the number of families with at most one girl is: 112 + 314

i.e.

Number of Girls : 0 ----> 1

Number of Families: 112 -> 314

So, we have:

$At\ Most\ One\ Girl = 112 + 314$

$At\ Most\ One\ Girl = 426$

The probability is then calculated as:

$Probability = \frac{At\ Most\ One\ Girl}{Total}$

$Probability = \frac{426}{1000}$

$Probability = 0.426$

Solving (b): More girls

From the table, the number of families with more girl is: 382 + 192

i.e.

Number of Girls : -----> 2 ------->3

Number of Families: --> 382 ---> 192

So, we have:

$More\ Girls = 382 + 192$

$More\ Girls = 574$

The probability is then calculated as:

$Probability = \frac{More\ Girls}{Total}$

$Probability = \frac{574}{1000}$

$Probability = 0.574$

4 0

2 years ago