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barxatty [35]
3 years ago
11

What is 6x-2y=30 equal to and what is its x intercept

Mathematics
1 answer:
vesna_86 [32]3 years ago
3 0
You can divide it on 2 and it will still be the same
3x-y=15 is equal to 6x-2y=30
So; the answer is: 3x-y=15
its x intercept dividing on 3.
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If a factory continuously dumps pollutants into a river at the rate of the quotient of the square root of t and 45 tons per day,
julsineya [31]
<h2>Hello!</h2>

The answer is:

The first option, the amount dumped after 5 days is 0.166 tons.

<h2>Why?</h2>

To solve the problem, we need to integrate the given expression and evaluate using the given time.

So, integrating we have:

\int\limits^5_0 {\frac{\sqrt{t} }{45} } \, dt=\int\limits^5_0 {\frac{1}{45} (t)^{\frac{1}{2} } } \, dt\\\\\int\limits^5_0 {\frac{1}{45} (t)^{\frac{1}{2} } } \ dt=\frac{1}{45}\int\limits^5_0 {t^{\frac{1}{2} } } } \ dt\\\\\frac{1}{45}\int\limits^5_0 {t^{\frac{1}{2} } } } \ dt=(\frac{1}{45}*\frac{t^{\frac{1}{2}+1} }{\frac{1}{2} +1})/t(5)-t(0)\\\\(\frac{1}{45}*\frac{t^{\frac{1}{2}+1} }{\frac{1}{2} +1})/t(5)-t(0)=(\frac{1}{45}*\frac{t^{\frac{3}{2}} }{\frac{3}{2}})/t(5)-t(0)

(\frac{1}{45}*\frac{t^{\frac{3}{2}} }{\frac{3}{2}})/t(5)-t(0)=(\frac{1}{45}*\frac{2}{3}*t^{\frac{3}{2} })/t(5)-t(0)\\\\(\frac{1}{45}*\frac{2}{3}*t^{\frac{3}{2} })/t(5)-t(0)=(\frac{2}{135}*t^{\frac{3}{2}})/t(5)-t(0)\\\\(\frac{2}{135}*t^{\frac{3}{2}})/t(5)-t(0)=(\frac{2}{135}*5^{\frac{3}{2}})-(\frac{2}{135}*0^{\frac{3}{2}})\\\\(\frac{2}{135}*5^{\frac{3}{2}})-(\frac{2}{135}*0^{\frac{3}{2}})=\frac{2}{135}*11.18-0=0.1656=0.166

Hence, we have that the amount dumped after 5 days is 0.166 tons.

Have a nice day!

5 0
3 years ago
Total health care costs in the United States in 2003 were $2,000,000,000,000. Express this number in scientific notation.
Elan Coil [88]

2^12 power please give me stars and points


5 0
3 years ago
Select the correct answer.<br> Identify the axis of symmetry of the function graphed below.
Nady [450]

Answer:

D. x = -1.

Step-by-step explanation:

I have attached an explanation to your problem. Please see the attachment  below.

3 0
3 years ago
Read 2 more answers
Neighborhood block:
katen-ka-za [31]

Answer:

<u>The width of the neighborhood block is 0.05 or 1/20 miles</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Number of times Bijan run around the neighborhood block = 20

Total distance Bijan run = 8 miles

Length of the block = 3/20 = 0.15 miles

2. Use the formula for the perimeter of the neighborhood block and the reciprocal to find the width w of the city block.

Let's find the perimeter of the neighborhood block and the width, this way:

A. Rule of Three Direct for find the perimeter:

Laps              Distance

20                   8 miles

1                       x miles

x * 20 = 8

20x = 8

x = 8/20

x = 2/5 or 0.4 miles

B. Formula of the perimeter to find the width

Perimeter = 2 Length + 2 Width

Replacing with the real values we know:

0.4 = 2 * 0.15 + 2w

0.4 = 0.3 + 2w

0.4 - 0.3 = 2w

0.1 = 2w

w = 0.1/2

w = 0.05 miles

<u>The width of the neighborhood block is 0.05 or 1/20 miles</u>

8 0
3 years ago
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Identify the kind of sample that is described
ELEN [110]

Answer:

Cluster sampling

Step-by-step explanation:

Choosing groups and sampling whole group.

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2 years ago
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