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3 years ago

I can’t figure this out at all.

Mathematics

1 answer:

Liula [17]3 years ago

6 0

The fact that this triangle is a right angle triangle makes you now have 2 angles and the 1 side given, so it should be solvable.
First, You know that A=46 and C=90 as it is the right angle, and you know that the sum of any triangle's angles is 180. so now B=180-(90-46)=44
Now to the sides,
sin(B)=opp./hyp.=b/c=8/c=sin(44)
so, c=8/sin(44) which is approximately 11.52 unit length
now, use Pythagoras to find a,
a=√c²-b² =√11.52²-8² which is approximately 8.3 unit length.
Hope this helps.

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Graph the line with slope 1/2 passing through the point (-4,4).

Yakvenalex [24]

Answer:

Step-by-step explanation:

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It's a straight line, so you need 1 additional point.

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Plot (-4,4)

Slope 1/2 --> y increases 2 for each 1 of x increase.

Add 1 to x, and 2 to y ---> (-3,6)

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3 years ago

Sara spent half of her allowance going to the movies. She washed the family car and earned 9 dollars. What is her weekly allowan

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$7, I think. I would not be too sure about it, though.

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3 years ago

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Katyanochek1 [597]

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1. 42

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3 years ago

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Bonds from the city of tavel gorge worth $1,000 each are selling at 110.611. if sean wishes to purchase three such bonds, how mu

umka2103 [35]

The amount that will be expected to be paid for the bonds that are bought will be C. $3,318.33

<h3>How to calculate the amount of bonds?</h3>

From the information given, the bonds from the city of tavel gorge worth $1,000 each are selling at 110.611 and Sean wishes to purchase three such bonds.

Therefore, the amount for the bonds will be:

= 1110.611 × 3

= 3,318.33

In conclusion, the correct option is C.

Learn more about bonds on:

brainly.com/question/2775110

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2 years ago

The mean number of hours per day spent on the phone, according to a national survey, is four hours, with a standard deviation of

Reika [66]

Answer:

The new mean is 5.

The new standard deviation is also 2.

Step-by-step explanation:

Let the sample space of hours be as follows, S = {x₁, x₂, x₃...xₙ}

The mean of this sample is 4. That is, $\bar x=\frac{x_{1}+x_{2}+x_{3}+...+x_{n}}{n}=4$

The standard deviation of this sample is 2. That is, $s=\frac{1}{n-1}\sum (x_{i}-\bar x)^{2}=2$ .

Now it is stated that each of the sample values was increased by 1 hour.

The new sample is: S = {x₁ + 1, x₂ + 1, x₃ + 1...xₙ + 1}

Compute the mean of this sample as follows:

$\bar x_{N}=\frac{x_{1}+1+x_{2}+1+x_{3}+1+...+x_{n}+1}{n}\\=\frac{(x_{1}+x_{2}+x_{3}+...+x_{n})}{n}+\frac{(1+1+1+...n\ times)}{n}\\=\bar x+1\\=4+1\\=5$

The new mean is 5.

Compute the standard deviation of this sample as follows:

$s_{N}=\frac{1}{n-1}\sum (x_{i}-\bar x)^{2}\\=\frac{1}{n-1}\sum ((x_{i}+1)-(\bar x+1))^{2}\\=\frac{1}{n-1}\sum (x_{i}+1-\bar x-1)^{2}\\=\frac{1}{n-1}\sum (x_{i}-\bar x)^{2}\\=s$

The new standard deviation is also 2.

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4 years ago