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2 years ago

15

There are some Chicken and rabbits in a cage. There are 20 heads and 62 feet in total, the question is: how many chicken and rab

bits in the cage?

1 answer:

horsena [70]2 years ago

5 0

Answer:There are 72 heads (chicken and rabbit) and 200 legs. How many chickens and rabbits are present totally?

Step-by-step explanation

There are 72 heads (chicken and rabbit) and 200 legs. How many chickens and rabbits are present totally?

Legs of a chicken = 2

Legs of a rabbit = 4

Total heads = 72

Total legs= 200

Let's assume that each of them has minimum 2 legs.

So 72*2 = 144 legs

Remaining legs: 200-144= 56

These remaining legs belong to rabbit because rabbit has 4 legs each.

2*Rabbits= 56

Rabbits= 56/2 = 28

Out of 72, 28 are rabbits. So there are 72-28= 44 chicken.

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Find the slope and y intercept of the line y=7/5x-3 5/7; 3 3; 7/5 7/5;-3 -3; 7/5

7nadin3 [17]

Step-by-step explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

From the question

y = 7/5x - 3

Comparing with the above formula

<h3>Slope / m = 7/5</h3><h3>c/ y intercept = - 3</h3>

Hope this helps you

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2 years ago

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I need helpp its my final exam

Mashcka [7]

Answer:

hey i believe that your answer is A. without having to do the math if you look at it you can tell that its bigger then options B and C so those are not it. and it is to small to be D. so with that said your answer is A have a nice dy and good luck!

Step-by-step explanation:

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2 years ago

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Pls help!!!!!!!!!!!!!!!!!!!!!!

azamat

Answer:

the answer is 35 over 102 or 35/102

Step-by-step explanation:

so first we turn that 1 and 1/5 into 6/5 and then we flip the numbers into 5/6. so now we multiply 7/17 x 5/6 = 35/102. The Number can not be reduced.

Brainliest if you liked the answer.

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2 years ago

I need answer how to do number 3

Olegator [25]

You know that you need two already to make one hexagon. So, if you multiply, or add two four times, 2+2+2+2, you would get eight.

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3 years ago

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1. an alloy contains zinc and copper in the ratio of 7:9 find weight of copper of it had 31.5 kgs of zinc.

m_a_m_a [10]

Answer:

Step-by-step explanation:

Question (1). An alloy contains zinc and copper in the ratio of 7 : 9.

If the weight of an alloy = x kgs

Then weight of copper = $\frac{9}{7+9}\times (x)$

= $\frac{9}{16}\times (x)$

And the weight of zinc = $\frac{7}{7+9}\times (x)$

= $\frac{7}{16}\times (x)$

If the weight of zinc = 31.5 kg

31.5 = $\frac{7}{16}\times (x)$

x = $\frac{16\times 31.5}{7}$

x = 72 kgs

Therefore, weight of copper = $\frac{9}{16}\times (72)$

= 40.5 kgs

2). i). 2 : 3 = $\frac{2}{3}$

4 : 5 = $\frac{4}{5}$

Now we will equalize the denominators of each fraction to compare the ratios.

$\frac{2}{3}\times \frac{5}{5}$ = $\frac{10}{15}$

$\frac{4}{5}\times \frac{3}{3}=\frac{12}{15}$

Since, $\frac{12}{15}>\frac{10}{15}$

Therefore, 4 : 5 > 2 : 3

ii). 11 : 19 = $\frac{11}{19}$

19 : 21 = $\frac{19}{21}$

By equalizing denominators of the given fractions,

$\frac{11}{19}\times \frac{21}{21}=\frac{231}{399}$

And $\frac{19}{21}\times \frac{19}{19}=\frac{361}{399}$

Since, $\frac{361}{399}>\frac{231}{399}$

Therefore, 19 : 21 > 11 : 19

iii). $\frac{1}{2}:\frac{1}{3}=\frac{1}{2}\times \frac{3}{1}$

$=\frac{3}{2}$

$\frac{1}{3}:\frac{1}{4}=\frac{1}{3}\times \frac{4}{1}$

= $\frac{4}{3}$

Now we equalize the denominators of the fractions,

$\frac{3}{2}\times \frac{3}{3}=\frac{9}{6}$

And $\frac{4}{3}\times \frac{2}{2}=\frac{8}{6}$

Since $\frac{9}{6}>\frac{8}{6}$

Therefore, $\frac{1}{2}:\frac{1}{3}>\frac{1}{3}:\frac{1}{4}$ will be the answer.

IV). $1\frac{1}{5}:1\frac{1}{3}=\frac{6}{5}:\frac{4}{3}$

$=\frac{6}{5}\times \frac{3}{4}$

$=\frac{18}{20}$

$=\frac{9}{10}$

Similarly, $\frac{2}{5}:\frac{3}{2}=\frac{2}{5}\times \frac{2}{3}$

$=\frac{4}{15}$

By equalizing the denominators,

$\frac{9}{10}\times \frac{30}{30}=\frac{270}{300}$

Similarly, $\frac{4}{15}\times \frac{20}{20}=\frac{80}{300}$

Since $\frac{270}{300}>\frac{80}{300}$

Therefore, $1\frac{1}{5}:1\frac{1}{3}>\frac{2}{5}:\frac{3}{2}$

V). If a : b = 6 : 5

$\frac{a}{b}=\frac{6}{5}$

$=\frac{6}{5}\times \frac{2}{2}$

$=\frac{12}{10}$

And b : c = 10 : 9

$\frac{b}{c}=\frac{10}{9}$

Since a : b = 12 : 10

And b : c = 10 : 9

Since b = 10 is common in both the ratios,

Therefore, combined form of the ratios will be,

a : b : c = 12 : 10 : 9

7 0

2 years ago