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Mars2501 [29]
3 years ago
13

Megan ate 3/4 of a cookie write an equivalent fraction for the amount of cookie megan did not eat

Mathematics
1 answer:
dexar [7]3 years ago
4 0
Subtract what Megan ate from the whole.
4/4-3/4 = 1/4.
Megan did not eat 1/4th of the cookie
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Use exponent properties to simplify the following expression with a positive exponent.
Alecsey [184]

a^{-n}=\dfrac{1}{a^n}\\\\2^{-8}=\dfrac{1}{2^8}\\\\a^n\cdot a^m=a^{n+m}\\\\2^5\times2^1=2^{5+1}=2^6\\\\2^5\times2^{-8}\times2^1=\boxed{\dfrac{2^6}{2^8}}

3 0
3 years ago
7+7x=-70 what is the answer?
LenKa [72]

Answer: (-11)

Step-by-step explanation: 7+7x=-70

7-7+7x=-70-7

7x=-77

-77/7=-11

4 0
3 years ago
PLS HELP PLSSS HELP
Sonja [21]

The factored form of the given expressions are

y = (x -2)(x +7)

y = (x +6)(x -9)

y = (x +2)(x +6)

y = (x -5)(x -6)

y = (x +5)(x -5)

y = (x -1)(x +9)

y = (x +4)(x -4)

<h3>Factoring quadratic expressions</h3>

From the question we are to factor the given quadratic expressions

  • y = x² + 5x - 14

y = x² +7x -2x - 14

y = x(x +7) -2(x +7)

y = (x -2)(x +7)

  • y = x² -3x - 54

y = x² -9x +6x - 54

y = x(x -9) +6(x -9)

y = (x +6)(x -9)

  • y = x² +8x + 12

y = x² +6x +2x +12

y = x(x +6) +2(x +6)

y = (x +2)(x +6)

  • y = x² -11x +30

y = x² -6x -5x +30

y = x(x -6) -5(x -6)

y = (x -5)(x -6)

  • y = x² - 25

y = (x +5)(x -5)

  • y = x² + 8x - 9

y = x² +9x -x -9

y = x(x +9) -1(x +9)

y = (x -1)(x +9)

  • y = x² - 16

y = (x +4)(x -4)

Hence, the factored form of the given expressions are

y = (x -2)(x +7)

y = (x +6)(x -9)

y = (x +2)(x +6)

y = (x -5)(x -6)

y = (x +5)(x -5)

y = (x -1)(x +9)

y = (x +4)(x -4)

Learn more on Factoring quadratic expressions here: brainly.com/question/52959

#SPJ1

4 0
2 years ago
Read 2 more answers
The graph of the function f(x) = (x − 3)(x + 1) is shown.
Travka [436]

Answer:

Real values of x where x < -1

Step-by-step explanation:

Above the x-axis, the function is positive.

The function is decreasing when the gradient is negative.

The function has a positive

{x}^{2}

coefficient, therefore the vertex is a local minimum;

This means the gradients are negative before the vertex and positive after it;

To meet the conditions therefore, the function must be before the vertex and above the x-axis;

This will be anywhere before the x-intercept at x = -1;

Hence it is when x < -1.

8 0
3 years ago
Read 2 more answers
Given 2x² = -8, x is ____
IrinaVladis [17]

Answer:

2x² = -8

x² = -4

The answer is no real solutions (x ∉ R) because a perfect square cannot be negative.

5 0
3 years ago
Read 2 more answers
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