Actually the formula for the area of a triangle is A = 1/2bh.
First step: multiply both sides by 2, to get rid of the 1/2.
2A = bh
Now divide both sides by b.
2A/b = h or h = 2A/b
78, because you have to do the inverse operation so 80/2= 40 then 40-1= 39 and 39*3 = 78
Answer:
1, 5.8 represents the unit value. the slope is 5.8 so every time it moves over one vertical line it will go up 5.8 horizontal lines.
Step-by-step explanation:
Answer:
ρ_air = 0.15544 kg/m^3
Step-by-step explanation:
Solution:-
- The deflated ball ( no air ) initially weighs:
m1 = 0.615 kg
- The air is pumped into the ball and weight again. The new reading of the ball's weight is:
m2 = 0.624 kg
- The amount of air ( mass of air ) pumped into the ball can be determined from simple arithmetic between inflated and deflated weights of the ball.
m_air = Δm = m2 - m1
m_air = 0.624 - 0.615
m_air = 0.009 kg
- We are to assume that the inflated ball takes a shape of a perfect sphere with radius r = 0.24 m. The volume of the inflated ( air filled ) ball can be determined using the volume of sphere formula:
V_air = 4*π*r^3 / 3
V_air = 4*π*0.24^3 / 3
V_air = 0.05790 m^3
- The density of air ( ρ_air ) is the ratio of mass of air and the volume occupied by air. Expressed as follows:
ρ_air = m_air / V_air
ρ_air = 0.009 / 0.05790
Answer: ρ_air = 0.15544 kg/m^3
