X=6 is the answer to your question
Answer:
see explanation
Step-by-step explanation:
Using the trigonometric identity
tanx = 
Consider the left side
← divide terms on numerator/denominator by cotA
= 
= 
= right side , thus proven
Answer:
x *2 + (28-x)*4 = 100
Step-by-step explanation:
Given
Total number of questions in the paper = 28
Out of these 28 questions let us say that x number of questions are of 2 points and 28-x questions are of 4 points.
Also, the complete test is of 100 marks
Thus, the linear equation representing the
x *2 + (28-x)*4 = 100
Answer:
68.26% probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds
This is the pvalue of Z when X = 8.6 subtracted by the pvalue of Z when X = 6.4. So
X = 8.6



has a pvalue of 0.8413
X = 6.4



has a pvalue of 0.1587
0.8413 - 0.1587 = 0.6826
68.26% probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds
The answer is
u = -15, hope this helps!