3 years ago

Plz help me answer plz help

Mathematics

1 answer:

vazorg [7]3 years ago

4 0

55 days i hope this answer helps

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What is the equation of a line that passes through the point (8, 1) and is perpendicular to the line whose equation is y=−23x+5

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Answer:

$y-1=\frac{1}{23} (x-8)$

Step-by-step explanation:

We can write the equation of a line in 3 different forms including slope intercept, point-slope, and standard depending on the information we have. We have a point (8,1) and a slope from the equation y=-23x+5. We will chose point-slope since we have a point and slope.

Point slope: $y-y_1=m(x-x_1)$

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Write the equation of the line in fully simplified slope-intercept form.

iren2701 [21]

Y=Mx+b

Rise / run between any two points = slope (m)
Where the line crosses the y axis is (yint) (b)

Slope is -1/2
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So the equation is y=(-1/2)x - 8

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