Understanding:
The total number of students is 40. 8.20% of them were absent, which means the rest were present, or in other words, (100-8.20)% were present or 91.8%. We can find the actual number of present students by multiplying the percentage of present students by the total number of students.
Solution:
Present Percentage = 91.8% or 
Present Students = 
, since we are dealing with people we have to round it, so the present students are actually 37.
Answer:
p = 25,20 cm
h = 34,32 cm
A(min) = 864,86 cm²
Step-by-step explanation:
Let call p and h dimensions of a poster, ( length , and height respectively) and x and y dimensions of the printed area of the poster then
p = x + 8 and h = y + 12
Printed area = A(p) = 384 cm² and A(p) = x*y ⇒ y = A(p)/x
y = 384 / x
Poster area = A(t) = ( x + 8 ) * ( y + 12 ) ⇒ A(t) = ( x + 8 ) * [( 384/x ) + 12 ]
A(t) = 384 + 12x + 3072/x + 96 A(t) = 480 + 3072/x + 12x
A(t) = [480x + 12x² + 3072 ] / x
A´(t) = [(480 + 24x )* x - (480x + 12x² + 3072]/x²
A´(t) = 0 [(480 + 24x )* x - 480x - 12x² - 3072] =0
480x + 24x² -480x -12x² - 3072 = 0
12x² = 3072 x² = 296
x = 17,20 cm and y = 384/17,20 y = 22,32 cm
Notice if you substitu the value of x = 17,20 in A(t) ; A(t) >0 so we have a minimun at that point
Then dimensions of the poster
p = 17,20 + 8 = 25,20 cm
h = 22.32 + 12 =34,32 cm
A(min) = 25,20 *34.32
A(min) = 864,86 cm²
Answer:
576
Step-by-step explanation:
18 x 32 = 576
The single digit to the left of the vertical line is the tens units, the numbers to the right are the ones.
The scores above 64, would be 65, 73, 74, 77, 87, 88, 91, 93, 93, 97, 99, 99
A total of: 12 scores.
