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Arte-miy333 [17]

2 years ago

8

Malcolm buys a 5/6- pound bag of black beans and a 3/4- pound bag of pinto beans. how many pounds of beans does Malcolm buy in a

ll?

1 answer:

KonstantinChe [14]2 years ago

5 0

Answer:

5/6 + 3/4 = 19/12

Simplified answer would be 1 7/12

Step-by-step explanation:

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-1+5x≥-16 I dont know how to solve

olasank [31]

Answer: $x \ge -3$

Explanation:

Follow PEMDAS in reverse to undo what's happening to x.

We first add 1 to both sides, then divide both sides by 5 to fully isolate x.

Refer to the steps below to see what I mean.

$-1 + 5x \ge -16\\\\5x \ge -16+1\\\\5x \ge -15\\\\x \ge -15/5\\\\x \ge -3\\\\$

The inequality sign stays the same the entire time. The only time it flips is when you divide both sides by a negative number.

The solution set for x is anything -3 or larger.

If x was an integer, then we could say the solution set is {-3, -2, -1, 0, 1, 2, 3, 4, 5, 6, ...}

7 0

1 year ago

Help please important

Lemur [1.5K]

1) tan 41°= 30cm divide by y cm
y= 30 divide by tan-1 41°

3 0

3 years ago

Read 2 more answers

Rewrite the following integral in spherical coordinates.

lora16 [44]

In cylindrical coordinates, we have $r^2=x^2+y^2$ , so that

$z = \pm \sqrt{2-r^2} = \pm \sqrt{2-x^2-y^2}$

correspond to the upper and lower halves of a sphere with radius $\sqrt2$ . In spherical coordinates, this sphere is $\rho=\sqrt2$ .

$1 \le r \le \sqrt2$ means our region is between two cylinders with radius 1 and $\sqrt2$ . In spherical coordinates, the inner cylinder has equation

$x^2+y^2 = 1 \implies \rho^2\cos^2(\theta) \sin^2(\phi) + \rho^2\sin^2(\theta) \sin^2(\phi) = \rho^2 \sin^2(\phi) = 1 \\\\ \implies \rho^2 = \csc^2(\phi) \\\\ \implies \rho = \csc(\phi)$

This cylinder meets the sphere when

$x^2 + y^2 + z^2 = 1 + z^2 = 2 \implies z^2 = 1 \\\\ \implies \rho^2 \cos^2(\phi) = 1 \\\\ \implies \rho^2 = \sec^2(\phi) \\\\ \implies \rho = \sec(\phi)$

which occurs at

$\csc(\phi) = \sec(\phi) \implies \tan(\phi) = 1 \implies \phi = \dfrac\pi4+n\pi$

where $n\in\Bbb Z$ . Then $\frac\pi4\le\phi\le\frac{3\pi}4$ .

The volume element transforms to

$dx\,dy\,dz = r\,dr\,d\theta\,dz = \rho^2 \sin(\phi) \, d\rho \, d\theta \, d\phi$

Putting everything together, we have

$\displaystyle \int_0^{2\pi} \int_1^{\sqrt2} \int_{-\sqrt{2-r^2}}^{\sqrt{2-r^2}} r \, dz \, dr \, d\theta = \boxed{\int_0^{2\pi} \int_{\pi/4}^{3\pi/4} \int_{\csc(\phi)}^{\sqrt2} \rho^2 \sin(\phi) \, d\rho \, d\phi \, d\theta} = \frac{4\pi}3$

4 0

2 years ago

Write this ratio as a fraction in the simplest form 3 feet to 63 inches

Lana71 [14]

Answer: The answer is 1/21

Step-by-step explanation:

7 0

3 years ago

I have no clue what to do... please help

strojnjashka [21]

Answer:

Multiply the base by the exponent

Step-by-step explanation:

7 0

3 years ago