Answer:
0.95g of Ag we can produce
Explanation:
To solve this question we have to convert the mass of silver nitrate (AgNO₃) to moles. The moles of silver nitrate = Moles of Ag. Then, with molar mass of Ag we can know the mass of silver:
<em>Moles AgNO₃ -Molar mass: 169.87g/mol-:</em>
1.5g * (1mol / 169.87g) = 0.0088 moles Ag
<em>Mass Ag -Molar mass: 107.87g/mol-:</em>
0.0088 moles Ag * (107.87g / mol) =
<h3>0.95g of Ag we can produce</h3>
If the mass of the compound is 48 grams, that would mean 1 mole of that compound would also he 48 grams
Answer:
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