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Nesterboy [21]
3 years ago
15

If you have 1.5 grams of silver nitrate, how many grams of silver could you produce?

Chemistry
1 answer:
Sunny_sXe [5.5K]3 years ago
7 0

Answer:

0.95g of Ag we can produce

Explanation:

To solve this question we have to convert the mass of silver nitrate (AgNO₃) to moles. The moles of silver nitrate = Moles of Ag. Then, with molar mass of Ag we can know the mass of silver:

<em>Moles AgNO₃ -Molar mass: 169.87g/mol-:</em>

1.5g * (1mol / 169.87g) = 0.0088 moles Ag

<em>Mass Ag -Molar mass: 107.87g/mol-:</em>

0.0088 moles Ag * (107.87g / mol) =

<h3>0.95g of Ag we can produce</h3>
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At a certain temperature the rate of this reaction is first order in HI with a rate constant of :0.0632s
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Answer : The time taken for the reaction is, 28 s.

Explanation :

Expression for rate law for first order kinetics is given by :

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}

where,

k = rate constant  = 0.0632

t = time taken for the process  = ?

[A_o] = initial amount or concentration of the reactant  = 1.28 M

[A] = amount or concentration left time 't' = 1.28\times \frac{17}{100}=0.2176M

Now put all the given values in above equation, we get:

0.0632=\frac{2.303}{t}\log\frac{1.28}{0.2176}

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shepuryov [24]

Answer:

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Hey there!


We Know that:



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