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Nesterboy [21]
3 years ago
15

If you have 1.5 grams of silver nitrate, how many grams of silver could you produce?

Chemistry
1 answer:
Sunny_sXe [5.5K]3 years ago
7 0

Answer:

0.95g of Ag we can produce

Explanation:

To solve this question we have to convert the mass of silver nitrate (AgNO₃) to moles. The moles of silver nitrate = Moles of Ag. Then, with molar mass of Ag we can know the mass of silver:

<em>Moles AgNO₃ -Molar mass: 169.87g/mol-:</em>

1.5g * (1mol / 169.87g) = 0.0088 moles Ag

<em>Mass Ag -Molar mass: 107.87g/mol-:</em>

0.0088 moles Ag * (107.87g / mol) =

<h3>0.95g of Ag we can produce</h3>
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C9H13O3N

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Take the atomic mass of C=12.0, H=1.0, O=16.0 and N=14.0.

We can draw a chart (please view this on desktop so to avoid spacing errors):

Let the mass of Epinephrine be 100g.

                             C                       H                          O                              N

mass(g) :              59                      7.15                    26.2                         7.65

no. of moles : 59/12 =4.9167     7.15/1 = 7.15     26.2/16=1.6375 7.65/14=0.5464

(n.o.m. = mass/molar mass)

Ratio:   4.9167/0.5464 =9    7.15/0.5464=13      1.6375= 3      0.5464/0.5464 =1

(divide the n.o.m. by the smallest n.o.m., which is 0.5464 in this case, take the whole numbers)

So, the empirical formula will be: C9H13O3N

But this is still not yet the molecular formula. We have to ensure the molar mass is 183g/mol. Multiply the empirical formula by n.

So, let the molecular formula of Epinephrine be (C9H13O3N)n.

12x9n + 1x13n + 16x3n + 14n = 183

108n + 13n + 48n + 14n = 183

183 n = 183.

n = 1

Hence, the molecular formula is C9H13O3N.

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3 years ago
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