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Nesterboy [21]
2 years ago
15

If you have 1.5 grams of silver nitrate, how many grams of silver could you produce?

Chemistry
1 answer:
Sunny_sXe [5.5K]2 years ago
7 0

Answer:

0.95g of Ag we can produce

Explanation:

To solve this question we have to convert the mass of silver nitrate (AgNO₃) to moles. The moles of silver nitrate = Moles of Ag. Then, with molar mass of Ag we can know the mass of silver:

<em>Moles AgNO₃ -Molar mass: 169.87g/mol-:</em>

1.5g * (1mol / 169.87g) = 0.0088 moles Ag

<em>Mass Ag -Molar mass: 107.87g/mol-:</em>

0.0088 moles Ag * (107.87g / mol) =

<h3>0.95g of Ag we can produce</h3>
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3Co2 (aq) 6NO3(aq) 6Na (aq) 2PO43–(aq) → Co3(PO4)2(s) 6Na (aq) 6NO3(aq) Identify the net ionic equation for this reaction.
Burka [1]

Answer : The net ionic equation will be,

3Co^{2+}(aq)+2PO_4^{3-}(aq)\rightarrow Co_3(PO_4)_2(s)

Explanation :

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

The given balanced ionic equation will be,

3Co^{2+}(aq)+6NO_3^-(aq)+6Na^+(aq)+2PO_4^{3-}(aq)\rightarrow Co_3(PO_4)_2(s)+6Na^+(aq)+6NO_3^-(aq)

In this equation, NO_3^-(aq)\text{ and }Na^+(aq) are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

Thus, the net ionic equation will be,

3Co^{2+}(aq)+2PO_4^{3-}(aq)\rightarrow Co_3(PO_4)_2(s)

8 0
3 years ago
How many atoms of lead are contained in 0.532mol?​
Colt1911 [192]

Answer:

3.2043 x 10²³

Explanation:

No. of Mole of lead (Pb) = 0.532 mol

No. of atoms of lead = ?

Solution:

Formula Used to calculate

no. of moles = numbers of particles (ions, molecules, atoms) /Avogadro's number

Avogadro's no. = 6.023 x10²³

So,

The formula could be written as

no. of atoms of lead Pb = no. of moles x 6.023 x10²³

Put the values in above formula

no. of atoms of lead Pb = 0.532 mol x 6.023 x10²³

no. of atoms of lead Pb = 3.2043 x 10²³

so 3.2043 x 10²³ atoms of lead are contained in 0.532 mole.

6 0
3 years ago
Check wether all the answers are correct or not. please?​
zhenek [66]

Answer:

I dont now but I think it is correct

3 0
2 years ago
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7 0
3 years ago
How many helium nuclei fuse together when making carbon?
Gemiola [76]
The answer is the 3. Hope this helped!
8 0
3 years ago
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