As you move from left to right across a period,the number of valence electrons<span>-increases. </span>
Answer:
O The number of oxygen atoms in the reactants used by this process equals the total number of oxygen atoms in the products.
Explanation:
The statement that best describes how photosynthesis follows the law of conservation of mass is that the number of oxygen atoms in the reactants used by this process is equal to the total number of oxygen atoms in the products.
The equation of photosynthesis reaction is given as:
6CO₂ + 6H₂O → C₆ H₁₂ O₆ + 6O₂
According to the law of conservation of mass, matter is neither created nor destroyed during the course of a chemical reaction.
By the virtue of this, the number of oxygen atom on both sides of the expression must be the same. Also, the number of carbon and hydrogen atoms must also be the same.
Answer:
0.84M
Explanation:
Hello,
At first, the equilibrium constant should be computed because the whole situation is at the same temperature so it is suitable for the new condition, thus:
![K_{eq}=\frac{[NO]^2_{eq}}{[N_2]_{eq}[O_2]_{eq}} \\K_{eq}=\frac{0.6^2}{0.2*0.2}\\ K_{eq}=9](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BNO%5D%5E2_%7Beq%7D%7D%7B%5BN_2%5D_%7Beq%7D%5BO_2%5D_%7Beq%7D%7D%20%5C%5CK_%7Beq%7D%3D%5Cfrac%7B0.6%5E2%7D%7B0.2%2A0.2%7D%5C%5C%20K_%7Beq%7D%3D9)
Now, the new equilibrium condition, taking into account the change x, becomes:
![9=\frac{[NO]^2_{eq}}{[N_2]_{eq}[O_2]_{eq}}\\9=\frac{[0.9+2x]^2}{[0.2-x][0.2-x]}](https://tex.z-dn.net/?f=9%3D%5Cfrac%7B%5BNO%5D%5E2_%7Beq%7D%7D%7B%5BN_2%5D_%7Beq%7D%5BO_2%5D_%7Beq%7D%7D%5C%5C9%3D%5Cfrac%7B%5B0.9%2B2x%5D%5E2%7D%7B%5B0.2-x%5D%5B0.2-x%5D%7D)
Nevertheless, since the addition of NO implies that the equilibrium is leftward shifted, we should change the equilibrium constant the other way around:
![\frac{1}{9} =\frac{[N_2]_{eq}[O_2]_{eq}}{[NO]^2_{eq}}\\\frac{1}{9} =\frac{[0.2+x][0.2+x]}{[0.9-2x]^2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B9%7D%20%3D%5Cfrac%7B%5BN_2%5D_%7Beq%7D%5BO_2%5D_%7Beq%7D%7D%7B%5BNO%5D%5E2_%7Beq%7D%7D%5C%5C%5Cfrac%7B1%7D%7B9%7D%20%3D%5Cfrac%7B%5B0.2%2Bx%5D%5B0.2%2Bx%5D%7D%7B%5B0.9-2x%5D%5E2%7D)
Thus, we arrange the equation as:
Finally, the new concentration is:
![[NO]_{eq}=0.9-0.06=0.84M](https://tex.z-dn.net/?f=%5BNO%5D_%7Beq%7D%3D0.9-0.06%3D0.84M)
Best regards.
Explanation:
Force = Mass × Acceleration
20 = 2.0 × A
A = 20/2 = 10m/s^2
At the very least, an oxoacid must 1) be an acid and 2) contain oxygen.
Ba(OH)2 (barium hydroxide) is a strong base. HCN, HF, and hydrochloric acid (HCl) don't contain oxygen.
Nitrous acid (HNO2) is an acid, and it contains oxygen. And the acidic hydrogen is bonded to an oxygen. Thus, nitrous acid qualifies as an oxoacid.
I don't know if H2PO4 is a typo; if not, then it would properly be written as H2PO4⁻ since it's the first deprotonation product of phosphoric acid, H3PO4. In any case, H2PO4⁻ is still acidic, albeit weakly, and its acidic hydrogens are bonded to the oxygen atoms. Thus, "H2PO4" would qualify as an oxoacid (for that matter, H3PO4 would also be an oxoacid).
Chloric acid (HClO3) is an acid, and it contains oxygen; its acidic hydrogen is bonded to an oxygen atom. Thus, chloric acid qualifies as an oxoacid.
